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3 years ago

15

Susan's cell phone plan allows her to use 950 minutes per month with no additional charge she has 188 minutes left for this mont

h how many minutes has she already used this month

1 answer:

arsen [322]3 years ago

6 0

950 - 188 = 762
Susan used 762 minutes in this month already.

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The question is below (Giving Brainliest)

WITCHER [35]

Answer:

Hiya there!

Step-by-step explanation:

I'm pretty sure that its 80.

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Consider △RST and △RYX.

astra-53 [7]

Answer:

B. StartFraction R Y Over R S EndFraction = StartFraction R X Over R T EndFraction = StartFraction X Y Over T S EndFraction

i.e $\frac{RY}{RS}$ = $\frac{RX}{RT}$ = $\frac{XY}{TS}$

Step-by-step explanation:

Two or more shape or figures are similar when their sides and angles can be compared appropriately.

In the given figure, ΔRXY is within ΔRST. Since the two triangles are similar, then their length of sides can be compared in the form of required ratios.

So that by comparison,

$\frac{RY}{RS}$ = $\frac{RX}{RT}$ = $\frac{XY}{TS}$

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Selena is 6 years younger than Paul. In 15 years, Paul will be 4 times the age that Selena is now. Find their present ages.

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Answer:

<u>The ages of Paul and Selena are 13 and 7 years old.</u>

Step-by-step explanation:

Age of Paul = x

Age of Selena = x -6

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<u>Paul now is 13 years old and Selena is 7 years old. In 15 years, Paul will be 28, that is 4 times the present age of Selena.</u>

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2 years ago

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5^(-x)+7=2x+4 This was on plato

Setler79 [48]

Answer:

Below

I hope its not too complicated

$x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

Step-by-step explanation:

$5^{\left(-x\right)}+7=2x+4\\\\\mathrm{Prepare}\:5^{\left(-x\right)}+7=2x+4\:\mathrm{for\:Lambert\:form}:\quad 1=\left(2x-3\right)e^{\ln \left(5\right)x}\\\\\mathrm{Rewrite\:the\:equation\:with\:}\\\left(x-\frac{3}{2}\right)\ln \left(5\right)=u\mathrm{\:and\:}x=\frac{u}{\ln \left(5\right)}+\frac{3}{2}\\\\1=\left(2\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)-3\right)e^{\ln \left(5\right)\left(\frac{u}{\ln \left(5\right)}+\frac{3}{2}\right)}$

$Simplify\\\\\mathrm{Rewrite}\:1=\frac{2e^{u+\frac{3}{2}\ln \left(5\right)}u}{\ln \left(5\right)}\:\\\\\mathrm{in\:Lambert\:form}:\quad \frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}$

$\mathrm{Solve\:}\:\frac{e^{\frac{2u+3\ln \left(5\right)}{2}}u}{e^{\frac{3\ln \left(5\right)}{2}}}=\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}:\quad u=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)\\\\\mathrm{Substitute\:back}\:u=\left(x-\frac{3}{2}\right)\ln \left(5\right),\:\mathrm{solve\:for}\:x$

$\mathrm{Solve\:}\:\left(x-\frac{3}{2}\right)\ln \left(5\right)=\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right):\\\quad x=\frac{\text{W}_0\left(\frac{\ln \left(5\right)}{2e^{\frac{3\ln \left(5\right)}{2}}}\right)}{\ln \left(5\right)}+\frac{3}{2}$

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3 years ago