Question

Consider the neutralization reaction between CH3COOH and Sr(OH)2. Complete and balance the neutralization reaction, name the products, and write the net ionic equation.

Answer 1

In chemistry, neutralization or neutralisation (see spelling differences), is a chemical reaction in which an acid and a base react quantitatively with each other. In a reaction in water, neutralization results in there being no excess of hydrogen or hydroxide ions present in solution

 2CH3COOH + Sr(OH)2 → (CH3COO)2Sr + 2H2O 

ethanoic acid reacts with strontium hydroxide to produce strontium ethanoate plus water.

Answer 2

Answer: The net ionic equation is written above and the products formed are strontium acetate and water molecule.

Explanation:

Neutralization reaction is defined as the reaction in which an acid reacts with a base to produce a salt and also releases water molecule.

Net ionic equation of any reaction does not include any spectator ions.

Spectator ions are defined as the ions which does not get involved in a chemical equation. They are found on both the sides of the chemical reaction when it is present in ionic form.

The chemical equation for the reaction of acetic acid and strontium hydroxide is given as:

$2CH_3COOH(aq.)+Sr(OH)_2(aq.)\rightarrow Sr(CH_3COO)_2(aq.)+2H_2O(l)$

The products formed are strontium acetate and water molecule

Ionic form of the above equation follows:

$2H^+(aq.)+2CH_3COO^-(aq.)+Sr^{2+}(aq.)+2OH^-(aq.)\rightarrow Sr^{2+}(aq.)+2CH_3COO^-(aq.)+2H_2O(l)$

As, strontium and acetate ions are present on both the sides of the reaction. Thus, it will not be present in the net ionic equation and are spectator ions.

The net ionic equation for the above reaction follows:

$2H^+(aq.)+2OH^-(aq.)\rightarrow 2H_2O(l)$

Hence, the net ionic equation is written above and the products formed are strontium acetate and water molecule.