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blondinia [14]
3 years ago
8

Im hvaing a hard time getting the right answer

Chemistry
1 answer:
Tanya [424]3 years ago
6 0

Answer:

V=23.9mL

Explanation:

Hello!

In this case for the solution you are given, we first use the mass to compute the moles of CuNO3:

n=2.49g*\frac{1mol}{125.55 g}=0.0198mol

Next, knowing that the molarity has units of moles over liters, we can solve for volume as follows:

M=\frac{n}{V}\\\\V=\frac{n}{M}

By plugging in the moles and molarity, we obtain:

V=\frac{0.0198mol}{0.830mol/L}=0.0239L

Which in mL is:

V=0.0239L*\frac{1000mL}{1L}\\\\V=23.9mL

Best regards!

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A chemistry student needs 50.0 g of dimethyl sulfoxide for an experiment. By consulting the CRC handbook of chemistry and physic
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What is e cell (in units of volts) for a galvanic cell constructed from barium and manganese electrodes?
gulaghasi [49]

Main Answer: The standard electrode potential of galvanic cell constructed from barium and manganese electrode is 4.097.

Explanation:

When the galvanic cell constructed between Manganese and Barium, the half reactions will be as follows:

Mn2+(aq) + 2e-⟶ Mn(s)                                             E1 = −1.185

Ba2+(aq) + 2e-⟶ Ba(s)                                                 E2 = −2.912

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The galvanic cell standard electrode potential is given by E1 + E2 = 1.185 + 2.912 = 4.097 volts

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Standard electrode potential is defined as the measure of reducing power of any compound or element. Its units are volts.

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