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lianna [129]
3 years ago
7

How many grams of H2 will react with 350 g of N2?

Chemistry
1 answer:
miss Akunina [59]3 years ago
6 0

Answer:

10.80

Explanation:

As per the equation, let us calculate the mole ratio. N2+3H2→2NH3. As per the equation one mole of nitrogen  reacts with 1 mol of hydrogen.

In terms of mass. 28.01 g of nitrogen needs 3 mol of hydrogen or 6.048 g of hydrogen.

We can set up the ratio;

28.01 g of

l

N

2

needs  

6.048 g of

l

H

2

1 g of

l

N

2

needs  

6.048

28.01

g  of

l

H

2

50.0 g of

l

N

2

needs  

6.048

×

50.0

28.01

l

g of

l

H

2

=

10.80 g of

l

H

2

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PLEASE HELP! I DONT KNOW WHAT TO DO! ITS ALOT PLEASE HELP THO!
kirza4 [7]

Answer:

CuCl2 (aq) + (NH4)2CO3(aq) → NH4Cl(aq) + CuCO3(s)

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*Cu(2+)(aq)+ 2Cl(-)(aq) + 2NH4(+)(aq) + CO3(2-)(aq) →2NH4(+)(aq) + Cl(-)(aq) + CuCO3(s)

*Cu(2+)(aq)+ CO3(2-)(aq) → CuCO3(s)

*2HCl(aq) + 2MgCO3(s) → 2MgCl(aq) + H2O(l) + 2CO2(g)

* 2H(+)(aq) + 2Cl(-)(aq) + 2MgCO3(s) → 2Mg(2+)(aq) +2Cl(-) (aq) + H2O(l) + 2CO2(g)

* 2MgCO3(s) → 2Mg(2+)(aq) + H2O(l) + 2CO2(g)

*ZnCl2(aq) + 2AgC2H3O2(aq) → 2AgCl(s) + Zn(C2H3O2)2(aq)

*Zn(2+)(aq) + 2Cl(-)(aq) + 2Ag(+)(aq) + C2H3O2(-)(aq) → 2AgCl(s) + Zn(2+)(aq) 2C2H3O2(-)(aq)

*2Cl(-)(aq) + 2Ag(+)(aq)  → 2AgCl(s)

*MnO(s) + H2SO4(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*FeS(s) + 2HCl (aq) → FeCl2(aq) + H2S(g)

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Explanation:

In the first equation you only need to know the rules of solubility. All chlorides are solubles  except Ag+ Pb+2 and Hg2(2+) and most carbonates are insolubles

<em>For ionic equations</em> Start with a balanced molecular equation.  Break all soluble strong electrolytes (compounds with (aq) beside them) into their ions  indicate the correct formula and charge of each ion . Indicate the correct number of each ion  and write (aq) after each ion . Bring down all compounds with (s), (l), or (g) unchanged.

<em>For net ionic equations </em>Write the balanced molecular equation.  Write the balanced complete ionic equation.  Cross out the spectator ions that are present.  Write the "leftovers" as the net ionic equation.

Before this, te equation must be balanced.

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*Cu(2+)(aq)+ 2Cl(-)(aq) + 2NH4(+)(aq) + CO3(2-)(aq) →2NH4(+)(aq) + Cl(-)(aq) + CuCO3(s)

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* 2MgCO3(s) → 2Mg(2+)(aq) + H2O(l) + 2CO2(g)

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*Zn(2+)(aq) + 2Cl(-)(aq) + 2Ag(+)(aq) + C2H3O2(-)(aq) → 2AgCl(s) + Zn(2+)(aq) 2C2H3O2(-)(aq)

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*MnO(s) + 2H(+)(aq) + SO4(2-)(aq) → MnSO4(s) + H2O (l)

*FeS(s) + 2HCl (aq) → FeCl2(aq) + H2S(g)

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3 years ago
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leva [86]
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7 0
3 years ago
How many moles are in 2.1 x 10^{24} molecules SiO4
lozanna [386]

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Explanation:

Based on Avogadro's law:

1 mole of any substance has 6.02 x 10^23 molecules

So, 1 mole of SiO4 = 6.02 x 10^23 molecules

Zmoles of SiO4 = 2.1 x 10^{24} molecules

To get the value of Z, cross multiply:

(2.1 x 10^{24} molecules x 1mole) = (6.02 x 10^23 molecules x Z moles)

2.1 x 10^{24} molecules = (6.02 x 10^23 x Z)

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