This is an interesting question. I chose to tackle it using the Law of Cosines.
AC² = AB² + BC² - 2·AB·BC·cos(B)
AM² = AB² + MB² - 2·AB·MB·cos(B)
Subtracting twice the second equation from the first, we have
AC² - 2·AM² = -AB² + BC² - 2·MB²
We know that MB = BC/2. When we substitute the given information, we have
8² - 2·3² = -4² + BC² - BC²/2
124 = BC² . . . . . . . . . . . . . . . . . . add 16, multiply by 2
2√31 = BC ≈ 11.1355
(I know there isnt any real problem here to solve, but heres a tip on how to solve greatest to least with decimal problems)
1. Just because a number looks big, doesn't mean it is big
Example: 1.00000000000001 < 1.1
just look at the numbers ^ and dont just hastily read it over assuming that 1.1 is smaller because it "has less digits"
2. Negative numbers are... opposite. and they are less than positive numbers
-3.4 > -4.1
Why is this? Well, if you look on a line, with the point 0 in the middle, you can see that -3.4 is not as far away from 0 as -4.1 is. So the idea is to apply opposite logic for negative numbers
I hope these tips helped!! :D
Answer:
8
Step-by-step explanation:
Just flip it up... it will be 8
Draw a graph the function and find the value of x that produces the maximum
Answer - 3
B = 36/ (12-9*5)
B = 36/ (12- 45)
B = 36/ (-33)
E = N/A
D = 3
M = N/A
A = N/A
S = N/A