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3 years ago

Bubbles begin to appear in the vinegar and baking soda. The bubbles signal the formation of a(n)

Physics

1 answer:

bagirrra123 [75]3 years ago

3 0

Bubbles in a liquid almost always indicate the formation of an gas.

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What is a lot like gases but the atoms are different because they are made up of free electrons and ions of elements

34kurt

plasmas are a lot like gases

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3 years ago

A 6.7 kg object moves with a velocity of 8 m/s. what is its kinetic energy

blagie [28]

The Correct answer to this question for Penn Foster Students is: 214.4 J

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3 years ago

Read 2 more answers

in vision, the ____ stream controls identification of an object, and the ____ stream controls action toward the object.

prisoha [69]

Answer: In vision, the ventral stream controls identification of an object, and the dorsal stream controls action toward the object.

Explanation: The ventral stream is associated with object recognition and form representation.

Dorsal stream a pathway that carries visual information from the primary visual cortex to the parietal lobe.

Hope it helps :)

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2 years ago

What mechanism of energy is transferred by mass motion of fluid from one region of space to another?

lora16 [44]

Convection, because it is the process of heat transfer from one location to the next by the movement of fluids. The moving fluid carries energy within it.

5 0

3 years ago

A Carnot engine operates between temperature levels of 600 K and 300 K. It drives a Carnot refrigerator, which provides cooling

KATRIN_1 [288]

Explanation:

Formula for maximum efficiency of a Carnot refrigerator is as follows.

$\frac{W}{Q_{H_{1}}} = \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}$ ..... (1)

And, formula for maximum efficiency of Carnot refrigerator is as follows.

$\frac{W}{Q_{C_{2}}} = \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}}$ ...... (2)

Now, equating both equations (1) and (2) as follows.

$Q_{C_{2}} \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}}$ = $Q_{H_{1}} \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}$

$\gamma = \frac{Q_{C_{2}}}{Q_{H_{1}}}$

= $\frac{T_{C_{2}}}{T_{H_{1}}} (\frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{2}} - T_{C_{2}}})$

= $\frac{250}{600} (\frac{(600 - 300)K}{300 K - 250 K})$

= 2.5

Thus, we can conclude that the ratio of heat extracted by the refrigerator ("cooling load") to the heat delivered to the engine ("heating load") is 2.5.

4 0

3 years ago