Let the value of the car be represented by V and the amount of years by y.
This gives us the following formula:
V = 25,635 - 3000y
(This is because we start with a value of $25,635 and the value decreases by $3,000 every year 'y')
Now, we want to know when the car is worth $3,135, so we know V = 3,135
Now we can make up our equation:
25,365 - 3,000y = 3,135
Collecting terms gives us:
-3,000y = -22,500
Finally we divide by -3,000 to find 'y'
y = -22,500 / -3,000 = 7.5
Hence, the car will be worth $3,135 after 7.5 years.
Slop=(y2-y1)/(x2-x1)
Slop=(-2-(-7))/(-5-6)
Slop=-5/11
Answer:
7.25 × 10^6
Step-by-step explanation:
1) put into standard form: 6,000,000 + 1,250,000
2) add: 6,000,000 + 1,250,000= 7,250,000
3) put into scientific notation: 7.25 × 10^6
Answer:
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Step-by-step explanation:
