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3 years ago

Find the quotient of 1,979 divided by 13

Mathematics

2 answers:

Allisa [31]3 years ago

7 0

152.2 rounded to the nearest tenth

Marat540 [252]3 years ago

7 0

Your answer would have to be 152 with the remainder of 3

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in these triangles, side AB is congruent to side DF, and side BC is congruent to side FG. Determine the values of x and y

vlada-n [284]

I added a screenshot with the complete question

Answer:
x = 3
y = 9

Explanation:
1- getting the value of x:
We are given that:
side AB is congruent to side DF. This means that:
AB = DF
3(2x+10) = 12x + 12
6x + 30 = 12x + 12
12x - 6x = 30 - 12
6x = 18
x = 18/6
x = 3

2- getting the value of y:
We are given that:
side BC is congruent to side FG. This means that:
BC = FG
2y + 12 = 2(2y-3)
2y + 12 = 4y - 6
4y - 2y = 12 + 6
2y = 18
y = 18/2
y = 9

Hope this helps :)

5 0

3 years ago

Two numbers add to be 5 multiply to be -6

FrozenT [24]

Answer:

-1, 6

Step-by-step explanation:

x + y = 5

xy = -6

Take first equation and rewrite it. y = -x + 5

Then substitute the new equation in the second one.

x(-x + 5) = -6

-x^2 + 5x + 6 = 0

Divide by -1

x^2 - 5x - 6

(x + 1)(x - 6) = 0

x = -1, 6

3 0

3 years ago

How do I do number 28? My answer to 27 is 13. How would I calculate it?

Masja [62]

Average is the...basic number in the set. So, the one that is more relatable.
Based on that knowledge, just use your data that have or chose and find the most common one.
Hope this helps!

7 0

3 years ago

Read 2 more answers

Let’s assume that, over the years, a paper and pencil test of anxiety yields a mean score of 35 for all incoming college freshme

vovangra [49]

Answer:

|t| = 2.235 > 2.093

we rejected null hypothesis.

It is not coming from population

Step-by-step explanation:

Step:-1

Let’s assume that, over the years, a paper and pencil test of anxiety yields a mean score of 35 for all incoming college freshmen.

μ = 35

small sample size n =20

mean of the sample x⁻ = 30

standard deviation of (S) = 10

Null hypothesis :- The difference between x⁻ and μ is not significant

Alternative hypothesis:- The difference between x⁻ and μ is significant

that is μ ≠ 35

Level of significance :-∝ =0.05

The test statistic:-

$t = \frac{x^{-} - population mean}{\frac{S}{\sqrt{n} } }$

substitute all values in above equation

μ = 35 ,n =20

mean of the sample x⁻ = 30

standard deviation of (S) = 10

$t = \frac{30 - 35}{\frac{10}{\sqrt{20} } }$

t= -2.235

|t| = 2.235

The degrees of freedom γ =n-1 =20-1 =19

By tabulated value of 't' for 19 degrees of freedom at 5% level of significance.= 2.093 for two tailed test.(see attached diagram below)

conclusion:-

|t| = 2.235 > 2.093

we rejected null hypothesis.

It is not coming from population

8 0

3 years ago

Through: (-3, 3) and (0, -1)

Goshia [24]

Answer:

m=3/-4

Step-by-step explanation:

m= x(2)-x(1) / y(2)-y(1)=(0--3)/ (-1-3)=3/-4

7 0

2 years ago