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GenaCL600 [577]
3 years ago
15

Find the slope of the line that passes through (-61, 3) and (-41, 31)​

Mathematics
1 answer:
Alexus [3.1K]3 years ago
3 0

Answer:

im pretty sure its 1.4

Step-by-step explanation:

You might be interested in
Find the mode of the following number of countries randomly selected travelers visited in the past two years. 13,13,15,7,8,4,4,7
Aliun [14]

Answer:

The mode of the following number of countries randomly selected travelers visited in the past two years is 13.

Step-by-step explanation:

The mode of a data-set is the value that appears the most commonly, the most frequently.

In this data-set:

13 appears 3 times

7 and 4 twice

The others once

So 13 is the mode.

3 0
3 years ago
Solve 0.9(x-20)=830
Dmitry [639]

Answer:

942.22

Step-by-step explanation:

0.9(x-20)=830

Distribute .9

.9x -18 =830

Add 18 to each side

.9x -18+18=830+18

.9x = 848

Divide each side by .9

.9x/.9 = 848/.9

x =942.22222222

To the nearest hundredth

942.22

7 0
3 years ago
Suppose heights of seasonal pine saplings are normally distributed and have a known population standard deviation of 17 millimet
Mumz [18]

Answer:

296.693\leq x\leq 319.307

Step-by-step explanation:

The confidence interval for the population mean x can be calculated as:

x'-z_{\alpha /2}\frac{s}{\sqrt{n} } \leq x\leq x'+z_{\alpha /2}\frac{s}{\sqrt{n} }

Where x' is the sample mean, s is the population standard deviation, n is the sample size and z_{\alpha /2} is the z-score that let a proportion of \alpha /2 on the right tail.

\alpha is calculated as: 100%-99%=1%

So, z_{\alpha/2}=z_{0.005}=2.576

Finally, replacing the values of x' by 308, s by 17, n by 15 and z_{\alpha /2} by 2.576, we get that the confidence interval is:

308-2.576\frac{17}{\sqrt{15} } \leq x\leq 308+2.576\frac{17}{\sqrt{15} }\\308-11.307 \leq x\leq 308+11.307\\296.693\leq x\leq 319.307

6 0
3 years ago
Which expression is equivalent to the given expression?
Studentka2010 [4]
Which expression is equivalent to the given expression?

15(12-x)

A. 15*12-x


hope this help
4 0
3 years ago
5. A solid has a circle of radius r as its base. All sections of the solid perpendicular to the diameter along the x-axis are is
AleksandrR [38]

Answer:

 \frac{16r^3}{3}

Step-by-step explanation:

In this cross sections problem, we can integrate from -r to +r (so that the integral covers the entire base of the solid).

\int\limits^r_a {2(x^2+r^2 )} \, dx

The formatting for the integral did not let me put -r on the lower bound, so i replaced it with a, just know that a represents -r here.

Evaluating the integral gives use that it is equal to;

\frac{16r^3}{3}

Caution: this answer may not meet your needs, but this is the answer I have come up with with the given information.

If you found this answer helpful please consider leaving 5 stars, giving it a like, or if you asked this question, mark this answer as Brainliest. Thanks!

4 0
2 years ago
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