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Ivan
3 years ago
15

If the equation says that one cookie with 10 chips plus another cookie with 10 chips plus another cookie with 10 chips equal 30.

.2 bananas plus 2 bananas plus one cookie with 10 chips equal 14..2 bananas plus a clock at 3 o'clock plus another clock at 3 o'clock equal8..finally, a clock at 2 o'clock plus 1 banana plus 1 banana times 1 cookie with 7 chips equal what?

Mathematics
2 answers:
Shtirlitz [24]3 years ago
6 0
Wait what I don’t understand
tresset_1 [31]3 years ago
3 0
Because there are 3 sets of one cookie with 10 chips we can say that each set it worth 10 points. In the second equation has 1 set of cookies so we can subtract 10 points leaving us with 4 bananas that are equal to 4 points, this lets us know that each banana is worth 1 point. In the 3rd equation there are 2 bananas and if you subtract that you will have 6 points left that is equal to 2 clocks set at 3 o'clock. This tells us that each clock is worth whatever time it displays. In the final equation the closk set at 2 o'clock is worth 2 points and each banana is worth 1 point. Because the cookie only has 7 chips with it now it is not equal to 10. To divide it evenly the cookie would be worth 5 points and each chip is worth 0.5 points. So the cookie with 7 chips is equal to 8.5 points.
2 + 1 + 1 \times 8.5 = 11.5
Hope this helps!!

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The given measurements may or may not determine a triangle. If not, then state that no triangle is formed. If a triangle is form
Fofino [41]
<h3>Answer:</h3><h3>C = 28.2, A = 25.8, a = 6.5</h3>

See diagram below.

==============================================

Work Shown:

Given info is

B = 126 degrees

b = 12

c = 7

Use the Law of Sines to solve for angle C

sin(C)/c = sin(B)/b

sin(C)/7 = sin(126)/12

sin(C)/7 = 0.067418082864579

sin(C) = 7*0.067418082864579

sin(C) = 0.471926580052053

C = arcsin(0.471926580052053) or C = 180-arcsin(0.471926580052053)

C = 28.1594278560921 or C = 180-28.1594278560921

C = 28.1594278560921 or C = 151.840572143908

C = 28.2 or C = 151.8

We have two possible angle values for C.

-----------------

If C = 28.2, then A = 180-B-C = 180-126-28.2 = 25.8

If C = 151.8, then A = 180-B-C = 180-126-151.8 = -97.8

So it is not possible for C = 151.8 (because it leads to angle A being negative)

Therefore, only C = 28.2 is possible.

-----------------

Use the law of cosines to find the remaining side 'a'

a^2 = b^2 + c^2 - 2*b*c*cos(A)

a^2 = (12)^2 + (7)^2 - 2*(12)*(7)*cos(25.8)

a^2 = 144 + 49 - 168*0.900318771402194

a^2 = 144 + 49 - 151.253553595569

a^2 = 41.7464464044315

a = sqrt(41.7464464044315)

a = 6.46114900032738

a = 6.5

-----------------

Only one triangle is possible

The fully solved triangle has these angles and sides:

  • A = 25.8 (approx)
  • B = 126
  • C = 28.2 (approx)
  • a = 6.5 (approx)
  • b = 12
  • c = 7

With stuff in bold representing the terms we solved for previously. Attached below is an image of the fully solved triangle.

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