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Ivan
3 years ago
15

If the equation says that one cookie with 10 chips plus another cookie with 10 chips plus another cookie with 10 chips equal 30.

.2 bananas plus 2 bananas plus one cookie with 10 chips equal 14..2 bananas plus a clock at 3 o'clock plus another clock at 3 o'clock equal8..finally, a clock at 2 o'clock plus 1 banana plus 1 banana times 1 cookie with 7 chips equal what?

Mathematics
2 answers:
Shtirlitz [24]3 years ago
6 0
Wait what I don’t understand
tresset_1 [31]3 years ago
3 0
Because there are 3 sets of one cookie with 10 chips we can say that each set it worth 10 points. In the second equation has 1 set of cookies so we can subtract 10 points leaving us with 4 bananas that are equal to 4 points, this lets us know that each banana is worth 1 point. In the 3rd equation there are 2 bananas and if you subtract that you will have 6 points left that is equal to 2 clocks set at 3 o'clock. This tells us that each clock is worth whatever time it displays. In the final equation the closk set at 2 o'clock is worth 2 points and each banana is worth 1 point. Because the cookie only has 7 chips with it now it is not equal to 10. To divide it evenly the cookie would be worth 5 points and each chip is worth 0.5 points. So the cookie with 7 chips is equal to 8.5 points.
2 + 1 + 1 \times 8.5 = 11.5
Hope this helps!!

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Answer:

x = -9

Step-by-step explanation:

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\log_dabc=\log_da+\log_db+\log_dc

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\log_dc=\dfrac1{\log_cd}=\dfrac12

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###

Another way to do this:

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abc=(c^{-4/3})^{9/8}c^{-4/3}c=c^{-11/6}

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\log_dabc=\log_dc^{-11/6}=-\dfrac{11}6\log_dc=-\dfrac{11}6\cdot\dfrac12=-\dfrac{11}{12}

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