Answer:
The temperature of the weather station was 3 degrees Celcius an hour earlier.
Step-by-step explanation:
We can say that the weather an hour ago should be represented with the variable - x.
From the problem, we know that the temperature of the station falls at a rate of -3 degrees per hour. This means that for every hour, the temperature of the place will go down by about 3 degrees Celsius.
If the temperature of the weather station is currently 0 degrees Celsius, to find its temperature an hour earlier, it means that we will need to add 3 degrees to its current temperature, because that is what must have lost in one hour.
i.e x = 0 + 3 = 3 degrees Celcius.
This means that the temperature of the weather station was 3 degrees Celcius an hour earlier.
Answer:
a) 3 b) 5 c) 7 d) 9
Step-by-step explanation:
For this, you want to replace x in the equation y=x+5 with each of the values listed.
For the first one, -2, the equation becomes y=-2+5, which is solved to y=3.
For the second one, 0, the equation becomes y=0+5, which is solved to y=5.
For the third one, 2, the equation becomes y=2+5, which is solved to y=7.
For the last one, 4, the equation becomes y=4+5, which is solved to y=9.
**This content involves solving algebraic equations with a known variable, which you may wish to revise. I'm always happy to help!
Answer:
y=2x-5
Step-by-step explanation:
First simplify: y-1=2x-6
y-1=2(x-3)
First simplify and distribute everything.
<u>y-1=2x-6</u>
So, x equals 2 because it got distributed into the numbers inside the parenthesis. Same with the 2 and -3. They multiplied to become -6.
Since it's y-1=2x-6, you can simplify it even more so the -1 goes to the other side and turns into positive 1.
<u>y - 1 (+ 1) = 2x -6 (+ 1)</u>
-1(+1)=0 which leaves just the variable y on the <em><u>left side</u></em>.
-6(+1)=-5 which leaves 2x-5 on the <em><u>right side</u></em>.
This results in y=2x-5. Hope this helped ;)
-3p^3 + 5p -2p^2 - 4 - 12p + 5 + 8p^3
5p^3 - 2p^2 - 7p + 1
It is the second choice
take square root and subtract y2 from y1 and x2 from x1
