The number of days when the season pass would be less expensive than the daily pass is 5 days.
<h3>How many days would the season pass be less expensive?</h3>
The equation that represents the total cost of skiing with the daily pass : (daily pass x number of days) + (cost of renting skis x number of days)
$70d + $20d = $90d
The equation that represents the total cost of skiing with the seasonal pass : cost of season pass + (cost of renting skis x number of days)
$300 + $20d
When the season pass becomes less expensive, the inequality equation is:
Daily pass > season pass
$90d > $300 + $20d
In order to determine the value of d, take the following steps:
Combine and add similar terms: $90d - $20d > $300
70d > $300
Divide both sides by 70 d > $300 / 70
d > 4.3 days
Approximately 5 days.
To learn more about how to calculate inequality, please check: brainly.com/question/13306871
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Answer:
x=2/5, y=-24/5. (2/5, -24/5).
Step-by-step explanation:
y=-2x-4
y=1/2x-5
----------------
-2x-4=1/2x-5
-2x-1/2x-4=-5
-4/2x-1/2x=-5+4
-5/2x=-1
5/2x=1
x=1/(5/2)
x=2/5
y=1/2(2/5)-5
y=1/5-5
y=1/5-25/5
y=-24/5
18.75/75=(75/75) -
p =(75-18.5)/75
p=56.5/75
p=0.75(3recurring)
Answer:
44 +14i
Step-by-step explanation:
(5 + i)(9 + i)
FOIL
first 5*9 = 45
inner: 9i
outer :5i
last: i*i = i^2 = -1
Add togheter
45 + 9i+5i -1
Combine like terms
44 +14i
