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agasfer [191]
3 years ago
9

Mr. Rahman gave 40% of the money he had to his wife. he also gave 20% of the remaining amount to each of his 3 sons. half of the

amount now left was spent on miscellaneous items and the remaining amount of Rs.12000 was deposited in the bank. how much money did Mr. Rahman have initially
Mathematics
1 answer:
makkiz [27]3 years ago
7 0

Answer:

53760

Step-by-step explanation:

12000 x 2 = 24000

24000 x .20 = 4800 this is the amount he gave to each of his sons

4800 x 3 = 14400 this is the amount he gave to his sons in total

24000 + 14400 = 38400

38400 x .40 = 15360 this is how much he gave to his wife

15360 + 38400 = 53760

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Answer:

PQ = 5 units

QR = 8 units

Step-by-step explanation:

Given

P(-3, 3)

Q(2, 3)

R(2, -5)

To determine

The length of the segment PQ

The length of the segment QR

Determining the length of the segment PQ

From the figure, it is clear that P(-3, 3) and Q(2, 3) lies on a horizontal line. So, all we need is to count the horizontal units between them to determine the length of the segments P and Q.

so

P(-3, 3), Q(2, 3)

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Therefore, the length of the segment PQ = 5 units

Determining the length of the segment QR

Q(2, 3), R(2, -5)

(x₁, y₁) = (2, 3)

(x₂, y₂) = (2, -5)

The length between the segment QR is:

l=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

  =\sqrt{\left(2-2\right)^2+\left(-5-3\right)^2}

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  =\sqrt{8^2}

Apply radical rule: \sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

  =8

Therefore, the length between the segment QR is: 8 units

Summary:

PQ = 5 units

QR = 8 units

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