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frez [133]
3 years ago
14

Determine whether each pair of functions are inverses of each other.

Mathematics
1 answer:
MaRussiya [10]3 years ago
8 0

Answer:


Step-by-step explanation:



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Your deposit $1000 in an account that earns 2.5% annual interest. Find the balance after 2 years if the interest compounds with
BaLLatris [955]

Answer:

34%

Step-by-step explanation:

3+3+3+3+3+3+3+35%

8 0
2 years ago
What is the difference of the rational expressions below?
Korolek [52]

Answer:

in the pic

Step-by-step explanation:

answer A

.....

4 0
3 years ago
9. A rectangular garden has a length that is 3 feet longer than its width. Let w represent the width of the garden, in feet. The
inysia [295]

Answer:

B

Step-by-step explanation:

w=width

l=w+3

(w+4)=width+walkway(both sides)

(w+7)=length+walkway(both sides)

7 0
3 years ago
Find the value of x. Round to the nearest degree as needed.
Bas_tet [7]

9514 1404 393

Answer:

  x° = 29°

Step-by-step explanation:

The mnemonic SOH CAH TOA is intended to remind you of the relevant trig relationships. Here, you have the hypotenuse and the side opposite the unknown angle. So, the appropriate relation is ...

  Sin = Opposite/Hypotenuse

  sin(x°) = 12/25

  x° = arcsin(12/25) ≈ 28.69°

The value of x is about 29.

4 0
3 years ago
Joaquin is constructing the perpendicular bisector of ab. What should be his first step?
natali 33 [55]

Answer:

D. Open the compass so that the distance from the two points of the compass is wider than half the length of \over{AB}.

Step-by-step explanation:

To construct a perpendicular for \over{AB}, we must first take a compass & take the distance of its arms wider than half the length of \over{AB}.

This is done in order to get two intersecting arcs in the top & bottom of \over{AB} so that a perpendicular bisector can be drawn through it.

After two intersecting lines are drawn below & above \over{AB}, draw a line joining these 2 points through their points of intersection. The point where it intersects \over{AB} is the middle-most point of \over{AB} & now a perpendicular bisector of \over{AB} is constructed.

\rule{150pt}{2pt}

3 0
2 years ago
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