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Savatey [412]
4 years ago
7

Which expressions below are equivent to 2(2x+1)​

Mathematics
1 answer:
murzikaleks [220]4 years ago
6 0

Answer:

4x+2

Step-by-step explanation:

2*2x+2*1

4x+2

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Use 1 as a benchmark to compare 6/5 and 5/6
Rashid [163]
6/5 is greater than one by 1/5 while 5/6 is less than one by 1/6.
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3 years ago
The area of a carpet is 36x -12 square inches. If the width of the carpet is 3x - 1 inches, what is the length?
lapo4ka [179]

Answer:

12x

Step-by-step explanation:

area=length×width

length=area/width

=36x-12/3x-1

=12(3x-1)/3x-1

length =12x

3 0
3 years ago
Find The derivative of:(cosx/1+sinx)^3​
forsale [732]

Answer:

-\frac{3 \cdot cos^2x}{(1+sinx)^3}

Step-by-step explanation:

y = (\frac{cosx}{1+sinx})^3\\\\\frac{dy}{dx} = 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{dy}{dx}(\frac{cosx}{1+sinx})                        [ y = x^n\  \  \ =>  \  \  \  \frac{dy}{dx} = b \cdot x^{n-1} \ ]

    = 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{(1+sin x(-sinx) - cosx(cosx)}{(1+sinx)^2}\\\\     [\ \frac{u}{v} = \frac{v \dcot u'- u \cdot v'}{v^2}\ ]

    = 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x-sin^2x- cos^2x}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x- (sin^2x+ cos^2x)}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-sin x-1}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-1 \cdot(sin x+1)}{(1+sinx)^2}\\\\= 3 \cdot (\frac{cosx}{1+sinx})^2 \cdot \frac{-1}{(1+sinx)}\\\\

   = -3 \cdot \frac{cos^2x}{(1+sinx)^3}

   

5 0
3 years ago
NEED HELP ON THIS ASAP!!!!!!
Keith_Richards [23]

Answer: Choice B (If you need to do questions like this in the future i recommend using the desmos graphing calculator online, inputting the equations and comparing them)

8 0
2 years ago
Michael has 2 options to invest $10,000: 1. 4% Simple Interest for 10 years. 2. 3.25% Compound Interest for 10 years. Which will
maksim [4K]

Answer:

help i need the ansewer

Step-by-step explanation:

7 0
4 years ago
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