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Rashid [163]
3 years ago
5

Both Coca Cola and Benetton are global enterprises. Conduct online research and answer the following questions: What characteris

tics do these two firms display that qualify them as global enterprises?

Business
1 answer:
Bess [88]3 years ago
7 0

Answer: here’s a photo of sample answer

Explanation:

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Ben learns that the company was going to be laying off several employees over the next several months. He knew that the rumor mi
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D. Call an all staff meeting and give everyone the news at once.

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Instead of letting the rumors spread throughout the company, what Ben is supposed to do is have a meeting with his entire staff and let all of them know at once what's going on. This way, he will be clear and direct and won't allow for gossip to spread throughout his company and he himself will address the issue head-on. This way he won't leave room for misinterpretation as he will explain what is going to happen.

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Read 2 more answers
The cob Douglas production function is given by Q(K,L)=AK^1.4*L^1.6
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Part a) The Cob Douglas production function is given as:

Q(K,L)=AK^{1.4} L^ {1.6 } .

To show that this function is homogeneous with degree 3, we introduce be a parameter, t.

Q(tK,tL)=A(tK)^{1.4} (tL)^ {1.6 } .

Using properties of exponents, we on tinder:

Q(tK,tL)=At^{1.4}K^{1.4} t^ {1.6 }L^ {1.6 } .

This implies that:

Q(tK,tL)=t^{1.4} \times t^ {1.6 }(AK^{1.4} L^ {1.6 } )

Q(tK,tL)=t^{1.4 + 1.6}(AK^{1.4} L^ {1.6 } )

Simplify the exponent of t to get;

Q(tK,tL)=t^{3}(AK^{1.4} L^ {1.6 } )

Hence the function is homogeneous with degree, 3

Part b) To verify Euler's Theorem, we must show that:

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L}=3AK^{1.4}L^{1.6}

Verifying from the left:

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =K(1.4AK^{0.4} L^{1.6}) + L(1.6AK^{1.4} L^{0.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =1.4(AK^{1.4} L^{1.6}) + 1.6(AK^{1.4} L^{1.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =(1.4 +  1.6)(AK^{1.4} L^{1.6})

K\frac{\partial Q}{\partial \: K}+L\frac{\partial Q}{\partial \: L} =3(AK^{1.4} L^{1.6})

Q•E•D

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