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Mekhanik [1.2K]
4 years ago
8

How manufacturing time does the graph of the function below intersect or touch the x-axis y=-2x^2+3x+5

Mathematics
1 answer:
soldi70 [24.7K]4 years ago
7 0
The graph intersects the x-axis twice.  It intersects at the points of (-1,0) and (2.5,0). The graph is attached.

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Can someone help me out thanks!!
vichka [17]

Answer:

x = 8

Step-by-step explanation:

16/x = x/4

x²= 16 × 4

x² = 64

x = √64

x = 8

Hope this helps.

6 0
3 years ago
Read 2 more answers
(7x²+2x+5)+(3x²-8x-10)
Mariulka [41]
First you would simplify the equation <span>(7x²+2x+5)+(3x²-8x-10) lets start with the first part 
</span><span>(7x²+2x+5) 
</span>7x² + 2x which = 49x + 2x which also = 51x Then you add the last part (+5) 
51x + 5
Now you simplify the last part.
<span>(3x²-8x-10)
</span>3x²-8x which=9x - 8x which also = 1x or simply x Then add the last part (-10) Which you'll get x-10 
51x + 5) + (x - 10) = 52x -5
so your answer is 52x - 5
7 0
4 years ago
Solve the equation.<br> 6.4= 4x<br> Ox=2.4<br> Ox=1.6<br> Ox=4<br> Ox= 10.4
faltersainse [42]
Divide 4 on both sides, x=6.4/4 which is 1.6
4 0
3 years ago
Read 2 more answers
Graph A: A horizontal line goes from (1, 0.5) to (2, 0.5). Another horizontal line goes form (2, 0.2) to (7, (0, 2). Graph B: A
ZanzabumX [31]

Answer: neither graph A nor graph B, because, even though both curves are above the horizontal axis, neither graph has an area of 1

Step-by-step explanation:

<em>Areas under the graphs:</em>

<em />

<u>Graph A</u>

<u />(1)(0.5)+(7-2)(0.2)=1.5\\\\

<u>Graph B</u>

<u />\frac{\pi}{2}(1^{2})=\frac{\pi}{2}

As neither of these graphs have an area of 1, neither of them are density curves.

5 0
2 years ago
Read 2 more answers
02:23:02
lions [1.4K]

Answer:

(x + 2) \:  and  \: (x-6)

Step-by-step explanation:

{x}^{2}  - 14 - 12

{x}^{2}  + 2x - 6x - 12

x(x + 2) - 6(x + 2)

(x  + 2)(x  - 6)

<h3>Hope it is helpful....</h3>
4 0
3 years ago
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