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2 years ago

Which inequality is true?

Mathematics

2 answers:

kompoz [17]2 years ago

7 0

Answer:

thx for 5 points

Step-by-step explanation:

Viktor [21]2 years ago

5 0

Answer:

Step-by-step explanation:

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The following two-way table shows the data for the students of two different grades in a school:

xxMikexx [17]

Answer:

blabity-booo

Step-by-step explanation:

i love you ;)

3 0

2 years ago

Read 2 more answers

Help please, i have been stuck on this question for 20 minutes AND I DONT GET IT. Please help me.

Ratling [72]

Answer:

Step-by-step explanation:

sorry if im wrong

5 0

2 years ago

If X and Y are independent continuous positive random

Leni [432]

a) $Z=\frac XY$ has CDF

$F_Z(z)=P(Z\le z)=P(X\le Yz)=\displaystyle\int_{\mathrm{supp}(Y)}P(X\le yz\mid Y=y)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}P(X\le yz)P(Y=y)\,\mathrm dy$

where the last equality follows from independence of $X,Y$ . In terms of the distribution and density functions of $X,Y$ , this is

$F_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy$

Then the density is obtained by differentiating with respect to $z$ ,

$f_Z(z)=\displaystyle\frac{\mathrm d}{\mathrm dz}\int_{\mathrm{supp}(Y)}F_X(yz)f_Y(y)\,\mathrm dy=\int_{\mathrm{supp}(Y)}yf_X(yz)f_Y(y)\,\mathrm dy$

b) $Z=XY$ can be computed in the same way; it has CDF

$F_Z(z)=P\left(X\le\dfrac zY\right)=\displaystyle\int_{\mathrm{supp}(Y)}P\left(X\le\frac zy\right)P(Y=y)\,\mathrm dy$

$F_Z(z)\displaystyle=\int_{\mathrm{supp}(Y)}F_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Differentiating gives the associated PDF,

$f_Z(z)=\displaystyle\int_{\mathrm{supp}(Y)}\frac1yf_X\left(\frac zy\right)f_Y(y)\,\mathrm dy$

Assuming $X\sim\mathrm{Exp}(\lambda_x)$ and $Y\sim\mathrm{Exp}(\lambda_y)$ , we have

$f_{Z=\frac XY}(z)=\displaystyle\int_0^\infty y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=\frac XY}(z)=\begin{cases}\frac{\lambda_x\lambda_y}{(\lambda_xz+\lambda_y)^2}&\text{for }z\ge0\\0&\text{otherwise}\end{cases}$

and

$f_{Z=XY}(z)=\displaystyle\int_0^\infty\frac1y(\lambda_xe^{-\lambda_xyz})(\lambda_ye^{\lambda_yz})\,\mathrm dy$

$\implies f_{Z=XY}(z)=\lambda_x\lambda_y\displaystyle\int_0^\infty\frac{e^{-\lambda_x\frac zy-\lambda_yy}}y\,\mathrm dy$

I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.

6 0

3 years ago

Supplementary angles formed by parallel lines and transversals that are both outside the parallel line and on the opposite side

Mashcka [7]

Answer:

Alternate exterior angles

Step-by-step explanation:

Alternate exterior angles are angles that are formed outside two parallel lines that cuts through a transversal line. these angles are formed on the opposite side of the transversal line ( alternate side).

Also Alternate exterior angles are congruent in nature are they are not adjacent angles as well

4 0

2 years ago

Find the mode of the data. A. 25 B. 27 C. 27.5 D. 30

earnstyle [38]

The mode is the number that is repeated most often,
here, all the numbers appears just once so we don't have a mode

8 0

2 years ago