We are to form the combination of 6 objects taken 2 at a time. This can be expressed as 6C2
This means, there can be 15 different combinations of 2 members that can sit in the front row.
So, the answer to this question is option A
Given that E is a point between Point D and F, the numerical value of segment DE is 46.
<h3>What is the numerical value of DE?</h3>
Given the data in the question;
- E is a point between point D and F.
- Segment DF = 78
- Segment DE = 5x - 9
- Segment EF = 2x + 10
- Numerical value of DE = ?
Since E is a point between point D and F.
Segment DF = Segment DE + Segment EF
78 = 5x - 9 + 2x + 10
78 = 7x + 1
7x = 78 - 1
7x = 77
x = 77/7
x = 11
Hence,
Segment DE = 5x - 9
Segment DE = 5(11) - 9
Segment DE = 55 - 9
Segment DE = 46
Given that E is a point between Point D and F, the numerical value of segment DE is 46.
Learn more about equations here: brainly.com/question/14686792
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A; rate of change is the same as slope, so, using the slope formula,
, where
is the slope and
,
,
, and
are the
and
values.
Plug in
points for
and
, water level being the
and time being the
since we're looking for the answer in ft/hr-- you can choose any two, but from the same row.
ft/hr
V = lwh
2x³ + 17x² + 46x + 40 = l(x + 4)(x + 2)
2x³ + 12x² + 16x + 5x² + 30x + 40 = l(x + 4)(x + 2)
2x(x²) + 2x(6x) + 2x(8) + 5(x²) + 5(6x) + 5(8) = l(x + 4)(x + 2)
2x(x² + 6x + 8) + 5(x² + 6x + 8) = l(x + 4)(x + 2)
(2x + 5)(x² + 6x + 8) = l(x + 2)(x + 4)
(2x + 5)(x² + 2x + 4x + 8) = l(x + 4)(x + 2)
(2x + 5)(x(x) + x(2) + 4(x) + 4(2)) = l(x + 4)(x + 2)
(2x + 5)(x(x + 2) + 4(x + 2)) = l(x + 4)(x + 2)
(2x + 5)(x + 4)(x + 2) = l(x + 4)(x + 2)
(x + 4)(x + 2) (x + 4)(x + 2)
2x + 5 = l
Answer: y = 2x/3 - 5
Step-by-step explanation:
The equation of a straight line can be represented in the slope-intercept form, y = mx + c
Where c = intercept
Slope, m =change in value of y on the vertical axis / change in value of x on the horizontal axis represent.
The given line has a slope of 2/3 and it passes through (0,- 5)
To determine the intercept, we would substitute x = 0, y = - 5 and m= 2/3 into y = mx + c. It becomes
- 5 = 3/2 × 0 + c
c = - 5
The equation becomes
y = 2x/3 - 5
