Answer:
The maximum annual variable cost he can have to reach his projection is $1,940
Step-by-step explanation:
Given;
Number of miles drive per year N = 10,000 miles
Total annual Fixed cost F = $3,460
cost per mile(rate) r = $0.54 or less
Total cost = fixed cost + variable cost
Total cost = cost per mile × number of miles
Total cost = r × N = $0.54 × 10,000 = $5,400
Let V represent the total variable cost per year;
F + V ≤ r × N
Substituting the values;
3,460 + V ≤ 5,400
V ≤ 5,400 - 3,460
V ≤ 1,940
The maximum annual variable cost he can have to reach his projection is $1,940
Yes, because 89L = 89,000ml. So 89L 353mL = 89,353mL. Thus, 890,353mL is greater.
Answer:
4 feet
Step-by-step explanation:
Plz brainliest,hope I could Help
Answer:
- a(x) = 20 + 0.60x
- domain [0, 50]; range [20, 50]
- maybe
Step-by-step explanation:
a) If x liters are removed from a container with a volume of 50 L, the amount remaining in the container is (50 -x) liters. Of that amount, 40% is acid, so the acid in the container before any more is added will be ...
0.40 × (50 -x)
The x liters are replaced with 100% acid, so the amount of acid that was added to the container is ...
1.00 × (x)
Then after the remove/replace operation, the total amount of acid in the container is ...
a(x) = 0.40(50 -x) +1.00(x)
a(x) = 20 +0.60x . . . . . liters of acid in the final mixture
__
b) The quantity removed cannot be less than zero, nor can it be more than 50 liters. The useful domain of the function is 0 ≤ x ≤ 50. (liters)
The associated range is 20 ≤ a ≤ 50. (liters)
__
c) As we found in part b, the amount of acid in the final mixture may range from 20 liters to 50 liters. So, the percentage of acid in the final mix will range from 20/50 = 40% to 50/50 = 100%. The mixture could be 50% acid, but is not necessarily.
