Step 1: 1
(((x3) - (2•5x2)) + 29x) - 30 = 0
Step 2 2.1 x3-10x2+29x-30 is not a perfect cube
Step 3 Factoring: x3-10x2+29x-30
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 29x-30
Group 2: -10x2+x3
Pull out from each group separately :
Group 1: (29x-30) • (1)
Group 2: (x-10) • (x2)
3/3 or 3 over 3
usually its like 3
_
3
but it can go anyway
I’m not *completely* sure if this would be right, but it could possibly be:
160
how i got this:
20 = 150
/(divide) 150
0.13(recurring) = 1
x1200
160 = 1200
if you need me to explain anything in detail, please feel free to message! have a nice day:)<3