The area of the right triangle =
![\frac{1}{2}bh](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dbh)
b = base = SV = 12.3
h = hight = HL = 24.6
A = area
![\frac{1}{2}bh = A](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dbh%20%3D%20A)
I think it’s 6. There are 4 squares and 4 triangles. 2 triangles put together turn into a square, so that would make 2 extra squares. 4+2=6.
Answer:
B and C
Step-by-step explanation:
Just not linear lol
Answer:
Step-by-step explanation:
Area of an equilateral triangle = ![\frac{\sqrt{3}}{4} } a^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%20%7D%20a%5E%7B2%7D)
Sub in your value of 16ft
A = ![\frac{\sqrt{3}}{4} } *16^{2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7B3%7D%7D%7B4%7D%20%7D%20%20%2A16%5E%7B2%7D)
A = 110.85 ![ft^{2}](https://tex.z-dn.net/?f=ft%5E%7B2%7D)