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Scrat [10]
3 years ago
13

How to divide and simplify this radical expression

Mathematics
1 answer:
Evgen [1.6K]3 years ago
8 0

Answer:

  \dfrac{2x}{5}\sqrt[3]{50x^2}

Step-by-step explanation:

Since the root indices are the same, the fraction can be combined under one radical. Then you want to do two things:

  • factor out perfect cubes
  • make the denominator a perfect cube (so it can be factored out)

__

  \displaystyle\dfrac{\sqrt[3]{16x^8y^2}}{\sqrt[3]{5x^3y^2}}=\sqrt[3]{\dfrac{16x^8y^2}{5x^3y^2}}=\sqrt[3]{\dfrac{16x^5}{5}}=\sqrt[3]{\dfrac{(2x)^3\cdot2\cdot5^2x^2}{5^3}}\\\\=\boxed{\dfrac{2x}{5}\sqrt[3]{50x^2}}

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Part A<br> Rewrite 0.5 as an exponential expression with a base of 2.
koban [17]

Answer:

2^{-1}

Explanation:

05/10

Simplifying

1/2

or 2^-1

Hope this helps you. Do mark me as brainlist

4 0
2 years ago
Helppp me asap! plssss
zzz [600]

Answer 5x 1y 5 1

Step-by-step explanation:

4 0
3 years ago
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Alice Correa bought three yards of cloth to make a dress. The cloth was on sale for $1.93 per yard.
Ray Of Light [21]
Since the unit rate is $1.93 per yard, you need to multiply the number of yards by 1.93. So 1.93 x 3 = 5.79. Next, you convert 5% to a decimal, which is 0.05. Now, multiply 5.79 by 0.05, which is about 0.29. Finally, add 0.29 to 5.79, giving you the answer of 6.08. Alice payed $6.08; D.
4 0
3 years ago
A Cepheid variable star is a star whose brightness alternately increases and decreases. For a certain star, the interval between
sattari [20]

Answer:

a)

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) 0.09

Step-by-step explanation:

We are given the following in the question:

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)

where B(t) gives the brightness of the star at time t, where t is measured in days.

a) rate of change of the brightness after t days.

B(t) = 4.2 +0.45\sin\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(t) = 0.45\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\times \dfrac{2\pi}{4.4}\\\\B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)

b) rate of increase after one day.

We put t = 1

B'(t) = \dfrac{0.9\pi}{4.4}\cos\bigg(\dfrac{2\pi t}{4.4}\bigg)\\\\B'(1) = \dfrac{0.9\pi}{4.4}\bigg(\cos(\dfrac{2\pi (1)}{4.4}\bigg)\\\\B'(t) = 0.09145\\B'(t) \approx 0.09

The rate of increase after 1 day is 0.09

8 0
3 years ago
Given that p(b|a)=0.75 and p(a)=0.35, what is p(b and a)
Nikitich [7]

Answer:

1.0125

Step-by-step explanation:

Since b/a is 0.75 and a is given as 0.35

Then let's start by solving for b

Ok...how

b/a=0.75

a=0.35

Then make b the subject of formula

b=0.75×a

Then substitute the value of a

b=0.75×0.35

b=0.2625

Let's continue

b and a means b + a

0.75+0.2625

1.0125

Therefore the final answer is 1.0125

6 0
3 years ago
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