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slava [35]
4 years ago
7

Find the EXACT solution to the exponential equation 500=20(1.5)^(4x)

Mathematics
1 answer:
tangare [24]4 years ago
6 0
500=20(1.5)^{4x}\implies \cfrac{500}{20}=1.5^{4x}\implies 25=1.5^{4x}
\\\\\\
\textit{now, we'll take a common log, any will do, we'll use ln()}
\\\\\\
ln(25)=ln\left(1.5^{4x}  \right)\\\\
-----------------------------\\\\
log_{{  a}}\left( x^{{  b}} \right)\implies {{  b}}\cdot  log_{{  a}}(x)\\\\
-----------------------------\\\\
thus\implies ln(25)=4xln(1.5)\implies \cfrac{ln(25)}{4ln(1.5)}=x
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Can someone please teach how to do this .
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Answer:

Step-by-step explanation:

Let's take for example the first one Al(C2H2O2)

If there is no subscript under the number, the amount of atoms is 1

If we have a subscript, as in this case, the subscript is the number of atoms.

In the example above, there is 1 atom of Aluminium, two of Carbon, two of Hydrogen and 2 of Oxygen. If you have parenthesis and number before them, e.g., 4(Al2O3), you just multiply the parenthesis by the number in front of them, which means 4*2=8 aluminium atoms, 3*4=12 oxygen atoms, the same applies if the number is subscript behind the parenthesis like in fourth example.

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3 years ago
Your friend believes that he has found a route to work that would make your commute faster than what it currently is under simil
Strike441 [17]

Answer:

<em>The range of p-values </em>

<em>0.01 < p < 0.025 </em>

Step-by-step explanation:

<u><em>Explanation</em></u>:-

Given random sample size 'n' = 7

Assume that the populations are normally distributed

Null Hypothesis :H₀:μd=0.

Alternative Hypothesis:H₁:μd<0.

Degrees of freedom

ν = n-1 =7-1 =6

given the test statistic  t = - 3.201

we will use single tailed test in t-distribution table

<em>The test statistic t= 3.201 is lies between the critical values is 0.01 and 0.025</em>

<em>The range of p-values </em>

<em>0.01 < p < 0.025  (check t- distribution table single tailed test) </em>

<u><em>Final answer:- </em></u>

<em>The range of p-values </em>

<em>0.01 < p < 0.025 </em>

5 0
3 years ago
Jason wants to receive monthly payments of $3,250 for 15 years. How much does he have to invest now in an annuity that has an an
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The amount she should invest today in the annuity is $455,450.40.

<h3>How much should be invested today?</h3>

The first step is to determine the future value of the monthly annuity.

Future value = monthly payment x annuity factor

Annuity factor = {[(1+r)^n] - 1} / r

Where:

  • r = interest rate = 3.6/12 = 0.3%
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Future value : 3250 x [(1.003^180) - 1] / 0.003 = 774,171.92

The second step is to determine the present value of this future annuity:

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To learn more about annuities, please check: brainly.com/question/24108530

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2 years ago
Joel wanted his mom to buy a super-sized box of his favorite cereal, but his mom didn't think it would fit in her cupboard. The
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<h3><u>Given</u>:-</h3>

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<h3><u>To Find</u>:-</h3>

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<h3><u>Solution</u>:-</h3>

\\\diamond{\underline{\underline{\sf {\;\; Calculating\; Height\;  of  \; box :-}}}}\\

\\ \pink \star \:  \: {\underline{\boxed {\bf{  Volume_{ \red{ \{Rectangle \}}}  \: = l  \times w  \times  h }}} }\; \red\bigstar  \\

Where,

  • » l denotes Length
  • » w denotes Width
  • » h denotes Height

\\  \sf \implies \: {Volume_{ \red{ \{Rectangle \}}}  \: = l  \times w  \times  h} \\

\\  \sf \implies \: { 6,900 \:   = \: 23 \:    \times  \: 10 \:   \times  h} \\

\\  \sf \implies \: { 6,900 \:   = \:  230 \:   \times \:   h} \\

\\  \sf \implies \: {  \: h  \:   = \:   \frac{6900}{230}  \:  } \\

\\  \sf \implies \: {  \: h  \:   = \:   30 \: {cm }^{3}   \:   } \\

\\ \implies{\underline{\boxed{\frak { Height = 30  \: cm^3 }}}} \; \purple\bigstar \:  \\

\\\qquad \rule{120pt}{3pt}\\

Therefore , the Volume of the Box is 30 cm ³.

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2 years ago
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