As per your question, total cost of watermelon should end with either 5(for odd quantity) or 0(for even quantity).
If the quantity of watermelon is odd, then the total cost value of pineapple should end with 3 and this is not possible when the cost of pineapple is ₹7.
So let's come to conclusion that the count(quantity) of watermelon should be any one of 0, 2, 4, 6.
If count of watermelon is 6: It will cost ₹30 and for remaining ₹8, we can buy 1 pineapple but still ₹1 will not be utilised. So 1 pineapple is not possible
If count of watermelon is 4: It will cost ₹20 and for remaining ₹18, we can buy 2 pineapple with ₹4 not being utilised. So 2 pineapple is also not possible.
If count of watermelon is 2: It will cost ₹10 and for remaining ₹28, we can buy 4 pineapple with all amount being utilised. We can buy 4 pineapple along with with 2 watermelon for ₹38.
If count of watermelon is 0: It will cost you ₹0 and for remaining ₹38, we can buy 5 pineapple with ₹3 being not utilised. So 5 pineapple is also not possible.
So the answer is 4 pineapple.
Answer:
T stands for time
Step-by-step explanation:
Answer:
15-29= -14
(I need the explanation most importantly)
14+(-4) - 8 =10-8=2
(Explanation please)
-8.4 - (19.5.) = - 27.9, (just add them to each other and write -, because both have - in front of them)
(Explanation)
-15 + 8 - (-19.7) = - 7+19,7=12,7 (there is + and - so it will became - 7, and at next there is two - which will turn them into +)
(Explanation)
29.45 - 56.009 - 78.2=−104,759 (all you have to is to put them all together, and than make it 29.45 less, writing - in front of them)
(Explanation)
LAST ONE
45.9 - (-9.2) + 5= 45.9+9.2+5=55.1+5=60.1 (because when there is 2 minus next to each other it will became plus)
First add the prices of the original books.
2.5+4.95+6=11.45
Find 20% of 11.45
=2.29
Therefore I saved $2.29