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2 years ago

The numbers 97, 258 and 503 both include a five. Which statement is true about the value represented by the five in 503?

Mathematics

2 answers:

mamaluj [8]2 years ago

7 0

<span>b: it is 10 times the value represented by the five in 97258</span>

erastova [34]2 years ago

6 0

The answer is 503's 5's value is 500

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Suppose a square ABCD has a side length of 1 unit. The arcs BD and AC are circular arcs with centers at A and D, respectively. F

Likurg_2 [28]

Answer:

$1-\frac{\sqrt{3} }{4}-\frac{\pi}{6}$

Step-by-step explanation:

The missing figure is shown in the attachment

The area of the shaded region = Area of Square - (Area of sector AOB + Area of equilateral triangle BOC + Area of sector COD)

Area of Sector AOB=Area of Sector COD= $\frac{30}{360}*\pi*1^2=\frac{\pi}{12}$

Area of equilateral triangle = $\frac{1}{2}*r*\frac{\sqrt{3} }{2}*r= \frac{1}{2}*1*\frac{\sqrt{3} }{2}*=\frac{\sqrt{3} }{4}$

Area of shade region = $1^2-\frac{\sqrt{3} }{4}-\frac{\pi}{12}*2$

$1-\frac{\sqrt{3} }{4}-\frac{\pi}{6}$

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2 years ago

If a line contains the point (0, -1) and has a slope if 2, then which if the following points also lies on the line? (2, 1), (1,

Neko [114]

(1, 1) the slope is 2 and slopes can be read the easiest when expressed as a fraction (2/1) when the numerator (2) expresses how many digits you move the point up and the denominator (1) expresses how many points you move right

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2 years ago

Jerry’s rhombus has a base of 15 inches and a height of 9 inches. Charlene’s rhombus has a base and a height that are 13 the bas

neonofarm [45]

Answer: The area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

Step-by-step explanation:

I will assume that the exercise says " $\frac{1}{3}$ times the base and height of Jerry’s rhombus".

The area of a rhombus can be calculated with the following formula:

$A=b*a$

Where "b" is the length of the base and "a" is the altitude or the height.

Then, you can calculate the area using the formula shown above.

Therefore, you get:

1. Jerry's rhombus:

$A_1=(15\ in)(9\ in)\\\\A_1=135\ in^2$

2. Charlene's rhombus:

$A_2=(\frac{1}{3}*15\ in)(\frac{1}{3}*9\ in)\\\\A_2=(5\ in)(3\ in)\\\\A_2=15\ in^2$

Dividing the area calculated, you get:

$\frac{135\ in^2}{15\ in^2}=9$

Therefore, you can conclude that the area of Charlene's rhombus is nine times smaller than the area of Jerry's rhombus.

7 0

3 years ago

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Which equation has the same solution as x2 – 6x – 14 = 0?

grandymaker [24]

4x would be your answer

4 0

2 years ago

If 60 marks is 40%, how much is full marks (Show your working out)?

Vitek1552 [10]

' 40% ' means 0.4 .

You said that   60       = 0.4 x Full

Divide each side by 0.4 :    60 / 0.4 = 1 x Full

   Full = 150 .

8 0

3 years ago

Read 2 more answers