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Lelu [443]
3 years ago
9

Which of the following graphs is decreasing for all values of x?

Mathematics
1 answer:
sergeinik [125]3 years ago
5 0

Answer:

y

Step-by-step explanation:

please give branleist

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A monument in the shape of a right triangle sits on a rectangular pedestarl that is 7 meters high by 16 meters long. The longest
SashulF [63]

Answer:

height = 63  m

Step-by-step explanation:

The shape of the monument is a triangle. The triangle is a right angle triangle. The triangular monument is sitting on a rectangular pedestal that is 7 m high and 16 m long.  The longest side of the triangular monument is 65 m . The longest side of a right angle triangle is usually the hypotenuse. The adjacent side of the triangle which is the base of the triangle sitting on the rectangular pedestal is 16 m long.

Since the triangle  formed is a right angle triangle, the height of the triangular monument can be gotten using Pythagoras's theorem.

c² = a² + b²

where

c is the hypotenuse side while side a and b is the other sides of the right angle triangle.

65² - 16² = height²

height² = 4225  - 256

height² = 3969

square root both sides

height = √3969

height = 63  m

4 0
3 years ago
10 less than the product of
Snezhnost [94]

Answer:

x=45

Step-by-step explanation:

2/5x-10=8

2/5x=18

x=18÷2/5

x=18(5/2)

x=45

6 0
2 years ago
Read 2 more answers
Please help with geometry homework !!!
Umnica [9.8K]

You can solve this with next proportion =>

3 : 5 = 4 : x => 3x= 5*4 => 3x = 20 => x=20/3 = 6 (2/3)

The correct answer is  x= 6 (2/3)

Good luck!!!

5 0
3 years ago
A rectangle's length, x, is 2 meters greater than its width. If the perimeter of the rectangle is greater than 112 meters, what
kotykmax [81]
Assume widthis x-2
perimeter is 2*(width+length)
so 2*(x+x-1)>112
2*(2x-1)>112
4x-2>112
x>28.5
so any length greater than 28.5 will work
6 0
3 years ago
If a =-2 and b= 2 what will be the value of a^b
raketka [301]
Write out the equation;

y=a^b 
y=(-2)^2 
y=(-2)(-2) 
y=4 

Therefore, the value of a^b is 4 

Hope I helped :) 
7 0
3 years ago
Read 2 more answers
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