How do you draw a model that shows decimal 1.7

Mathematics

2 answers:

borishaifa [10]3 years ago

7 0

Draw two square that present the 1 and the 7 tenth you leave the first one as a whole that is 1.7 the 1 and for the second one you divide into 10 and shade 7 of them that represent the 7<span />

Pie3 years ago

3 0

Answer:

We can model the decimal number 1.7 by drawing two squares and divide each of the two squares into 10 equal parts.

Then we start shading the square such that the first square is fully shaded and in the second square we shade 7 out of the 10 parts such that 0.7 of the figure is shaded.

Hence, the total portion of the figures that are shaded are:

1+0.7=1.7

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Can you help me with numbers 20-22 please a lot of points

arsen [322]

We could find the slope with this formula
m = (y₂ - y₁)/(x₂ - x₁)
with (x₁,y₁) and (x₂,y₂) are the points that is located on the line.

NUMBER 20
Given:
(x₁,y₁) = (-2,3)
(x₂,y₂) = (7,-4)

Solution:
Input the points to the formula
m = (y₂ - y₁) / (x₂ - x₁)
m = (-4 - 3) / (7 - (-2))
m = -7 / (7+2)
m = -7/9

The slope of the line is -7/9

NUMBER 21
Given:
(x₁,y₁) = (-6,-1)
(x₂,y₂) = (4,1)

Solution:
Input the points to the formula
m = (y₂ - y₁) / (x₂ - x₁)
m = (1-(-1)) / (4 -(-6))
m = (1+1) / (4+6)
m = 2/10
m = 1/5

The slope of the line is 1/5

NUMBER 22
Given:
(x₁,y₁) = (-9,3)
(x₂,y₂) = (2,1)

Solution:
Input the points to the formula
m = (y₂ - y₁) / (x₂ - x₁)
m = (1 - 3) / (2 - (-9))
m = -2 / (2 + 9)
m = -2/11

The slope of the line is -2/11

6 0

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What is the surface area of the triangular prism?

Svetlanka [38]

Answer:

Step-by-step explanation:

Using pythag theorem we can find the last side of the triangle, which is equal to 5 after we have this we simply add up the areas of each individual shape like (1/2*3*4)+(1/2*3*4)+(6*5)+(3*6)+(4*6)

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Solve the system using either Gaussian elimination with back-substitution or Gauss-Jordan elimination. (If there is no solution,

Gnom [1K]

Answer:

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Step-by-step explanation:

$\left[\begin{array}{ccc|c}1&0&-3&-5\\3&1&2&4\\2&2&1&7\end{array}\right]$