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Doss [256]
3 years ago
10

3(2x−7)+ 1/ 3 (7x+2)

Mathematics
2 answers:
lord [1]3 years ago
8 0

Step-by-step explanation:

Hey there!

Given;

= 3(2x-7) + 1/3(7x+2)

<u>Let's</u><u> </u><u>simplify</u><u> </u><u>them</u><u>. </u>

<u>= 3(2x - 7) +  \frac{1}{3} (7x + 2)</u>

<u>= 6x - 21 +  \frac{7x + 2}{3}</u>

<u>= \frac{3(6x - 21) + 7x + 2}{3}</u>

<u>=  \frac{18x - 63 + 7x + 2}{3}</u>

<u>= \frac{25x - 61}{3}</u>

<u>Therefore the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>(</u><u>2</u><u>5</u><u>x-61</u><u>)</u><u>/</u><u>3</u><u>.</u>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

Marta_Voda [28]3 years ago
7 0

Answer:

\quad \frac{25x+2}{3}-21

Step-by-step explanation:

3(2x-7)+ 1/ 3 (7x+2)\\\\\mathrm{Expand}\:3\left(2x-7\right):\quad 6x-21\\=6x-21+\frac{1}{3}\left(7x+2\right)\\\\\mathrm{Expand}\:\frac{1}{3}\left(7x+2\right):\quad 7\times\frac{1}{3}x+2\times \frac{1}{3}\\\\=6x-21+7\times\frac{1}{3}x+2\times\frac{1}{3}\\\\\mathrm{Simplify}\:6x-21+7\times\frac{1}{3}x+2\times\frac{1}{3}:\\\\\quad \frac{25x+2}{3}-21

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4 0
3 years ago
A piggy bank of coins has quarters and dimes totaling $2.90. If there are 8 more dimes than quarters, how many of each coin is i
xenn [34]

Answer:

12 dimes and 4 quarters

Step-by-step explanation:

If a quarter is 25 cents and a dime is 10 cents then:

There are at least 8 dimes, so we have at least 80 cents

And we know there is only 8 more dimes than quarters so the ratio 12 dimes: 4 quarters tells us that this expression is correct

4 0
2 years ago
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andreev551 [17]
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5 0
3 years ago
The 2010 General Social Survey reported a sample where about 48% of US residents thought marijuana should be made legal. If we w
Sati [7]

Answer:

The sample size is  n  = 600

Step-by-step explanation:

From the question we are told that

    The  sample proportion is  \r  p = 0.48

     The  margin of error is  MOE  =  0.04

Given that the confidence level is 95%  the level of significance is mathematically represented as

        \alpha  =  100 - 95

        \alpha  =  5 \%

        \alpha  =  0.05

Next  we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table , the values is

                   Z_{\frac{\alpha }{2}  } =  1.96

The reason we are obtaining critical value of    \frac{\alpha }{2} instead of    \alpha is because  

\alpha represents the area under the normal curve where the confidence level interval (  1-\alpha) did not cover which include both the left and right tail while  

\frac{\alpha }{2} is just the area of one tail which what we required to calculate the margin of error

Generally the margin of error is mathematically represented as

      MOE  =  Z_{\frac{\alpha }{2} } *  \sqrt{ \frac{\r p(1-  \r p )}{n} }

substituting values

          0.04= 1.96*  \sqrt{ \frac{0.48(1-  0.48 )}{n} }

         0.02041 = \sqrt{ \frac{0.48(52 )}{n} }

         0.02041 = \sqrt{ \frac{ 0.2496}{n} }

          0.02041^2  = \frac{ 0.2496}{n}

           0.0004166 = \frac{ 0.2496}{n}

=>       n  = 600

   

5 0
3 years ago
I need help with my whole quiz but i will just start with this one plzzzz helpp!!!I
ElenaW [278]
It would be C I hope this helps
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3 years ago
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