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Doss [256]
3 years ago
10

3(2x−7)+ 1/ 3 (7x+2)

Mathematics
2 answers:
lord [1]3 years ago
8 0

Step-by-step explanation:

Hey there!

Given;

= 3(2x-7) + 1/3(7x+2)

<u>Let's</u><u> </u><u>simplify</u><u> </u><u>them</u><u>. </u>

<u>= 3(2x - 7) +  \frac{1}{3} (7x + 2)</u>

<u>= 6x - 21 +  \frac{7x + 2}{3}</u>

<u>= \frac{3(6x - 21) + 7x + 2}{3}</u>

<u>=  \frac{18x - 63 + 7x + 2}{3}</u>

<u>= \frac{25x - 61}{3}</u>

<u>Therefore the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>(</u><u>2</u><u>5</u><u>x-61</u><u>)</u><u>/</u><u>3</u><u>.</u>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

Marta_Voda [28]3 years ago
7 0

Answer:

\quad \frac{25x+2}{3}-21

Step-by-step explanation:

3(2x-7)+ 1/ 3 (7x+2)\\\\\mathrm{Expand}\:3\left(2x-7\right):\quad 6x-21\\=6x-21+\frac{1}{3}\left(7x+2\right)\\\\\mathrm{Expand}\:\frac{1}{3}\left(7x+2\right):\quad 7\times\frac{1}{3}x+2\times \frac{1}{3}\\\\=6x-21+7\times\frac{1}{3}x+2\times\frac{1}{3}\\\\\mathrm{Simplify}\:6x-21+7\times\frac{1}{3}x+2\times\frac{1}{3}:\\\\\quad \frac{25x+2}{3}-21

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<span>2x+ y = 3
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It looks like I could substitute the x=2y-1. Into 2x+y=3
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