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Maurinko [17]
3 years ago
10

PLEASE ANSWER FAST WILL DO BRAINLIESTThe coordinate grid shows points A through K. What point is a solution to the system of ine

qualities? y > −2x + 10 y > 1 over 2x − 2 coordinate grid with plotted ordered pairs, point A at negative 5, 4 point B at 4, 7 point C at negative 2, 7 point D at negative 7, 1 point E at 4, negative 2 point F at 1, negative 6 point G at negative 3, negative 10 point H at negative 4, negative 4 point I at 9, 3 point J at 7, negative 4 and point K at 2, 3 E K B D

Mathematics
1 answer:
Alja [10]3 years ago
4 0

Answer:  points B (4,7) and  I (9,3)

If the inequalities are

y > −2x + 10  and y> (½)x -2

Step-by-step explanation:  If I interpreted the inequalities correctly, the attached graph shows them. It is possible that you meant  y > 1/(2x-2) for the second inequality. If so, we start over!

You can test the values for all the points, but it appears that (4,7) and (9,3) both work.

The other coordinates appear to be outside the solution -- the dark-shaded area.

I hope this is your Brainliest answer. It was a lot of work!

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A dozen box of bagels costs $4.98. Because of inflation the price increases by 4% a year.
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Hope it helps:-)
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3 years ago
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5 0
3 years ago
Read 2 more answers
Can someone please find the vertex?
crimeas [40]
You have the correct axis of symmetry value. Nice work.

Plug that x value into the equation to get...
y = -2x^2 - 12x - 10
y = -2*(-3)^2 - 12*(-3) - 10 <<-- replace every x with -3; then use PEMDAS
y = -2*(9) - 12*(-3) - 10
y = -18 + 36 - 10
y = 18 - 10
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The vertex is the ordered pair (-3, 8)

Note: the axis of symmetry is the vertical line through the vertex

8 0
3 years ago
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almond37 [142]
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