r > 0 = r is greater than 0
r ≤ 8 = r is less than and equal to 8
0 ≤ r ≤ 8
I think the answer is 43.8.
23 plus 7 is 30. Now you multiply that by 5 to get 150.
Answer:
91.6 km/h
Step-by-step explanation:
Let v = average speed of van = 65 km/h and v' = average speed of car. Let t be the time the car starts to move. The van started 35 minutes earlier at t' = (t + 35/60) h.
Since distance d = vt where v = velocity and t = time, the distance moved by the van d = vt' = v(t + 35/60) and that moved by the car is d' = v't.
Since the car catches up with the van after it had moved a distance of 130 km, d = d' = 130 km.
So d = v(t + 0.583)
Substituting d = 130 km and v = 65 km/h, we have
130 km = 65 km/h(t + 0.583)
130 km = (65t + 37.895 )km
subtracting 37.895 from both sides, we have
130 km - 37.895 km = 65t
92.105 = 65t
dividing both sides by 65, we have
t = 92.105/65
= 1.417 h
≅ 1.42 h
Since d = d' = v't,
v' = d'/t
= 130 km/1.42 h
= 91.55 km/h
≅ 91.6 km/h
So, the average speed of the car is 91.6 km/h
Answer:
sine^-1(48/60)
We take <u>inverse sine</u> because we don't have the angle we use SOHCAHTOA with. From p, we have an opposite side available, and a hypotenuse,
so based on sine it's sine, oppsosite, hypotenuse.
We take inverse sine because angle p isnt't given,
so
inverse sin (48/60) = <em><u>53 degrees = p</u></em>