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Novosadov [1.4K]
3 years ago
14

¿Cuáles son los procedimientos a ambos lados de la igualdad que se deben realizar para calcular el valor de la incógnita x en la

siguiente ecuación? 2x+5=7
Mathematics
1 answer:
PilotLPTM [1.2K]3 years ago
3 0

Answer:

Los procedimientos que se deben realizar para calcular la incógnita x en la ecuación 2x+5=7 son:

  1. <u><em>El 5 que está sumando a la izquierda del igual, se pasa a restar a la derecha del igual.</em></u>
  2. <u><em>El 2 que multiplica a x a la izquierda del igual, se pasa a dividir a la derecha del igual.</em></u>

Step-by-step explanation:

Siguiendo los procedimiento descritos en la respuesta, para calcular el valor de la incógnita:

  • 2x + 5 = 7

Seguimos el primer paso: <em>el 5 que está sumando a la izquierda del igual, se pasa a restar a la derecha del igual</em>:

  • 2x = 7 - 5

Seguimos el segundo paso: <em>el 2 que multiplica a x a la izquierda del igual, se pasa a dividir a la derecha del igual:</em>

  • x=\frac{7-5}{2}

Como puedes ver, así se despejaría la incógnita x y solo faltaría operar los datos en la ecuación para obtener la respuesta:

  • x=\frac{2}{2}
  • x=1

<u><em>El resultado que nos daría la incógnita x sería 1</em></u>. Podemos probar el resultado en la ecuación original para comprobar el resultado que obtuvimos:

  • 2x + 5 = 7
  • 2 *(1) + 5 = 7
  • 2 + 5 = 7
  • 7 = 7

Así, identificamos que los procesos realizados fueron correctos.

You might be interested in
If y is directly proportional to x square and y equal 1/8 when x = 1/2 what is the positive value of x when y it was 9/2?
mojhsa [17]

Answer:

d

Step-by-step explanation:

Given y is directly proportional to x² then the equation relating them is

y = kx² ← k is the constant of proportion

To find k use the condition y = \frac{1}{8} when x = \frac{1}{2}, then

\frac{1}{8} = k(\frac{1}{2} )² = \frac{1}{4} k ( multiply both sides by 8 )

1 = 2k ( divide both sides by 2 )

k = \frac{1}{2}

y = \frac{1}{2} x² ← equation of proportion

When y = \frac{9}{2} , then

\frac{9}{2} = \frac{1}{2} x² ( multiply both sides by 2 )

9 = x² ( take the square root of both sides )

x = ± \sqrt{9} = ± 3

with positive value x = 3 → d

8 0
4 years ago
Find the absolute maximum and absolute minimum values of f on the given interval. f(x) = 16 + 2x − x^2, [0, 5]
RSB [31]

Answer:

<h2>absolute maximum = 16</h2><h2>absolute minimum = 1</h2>

Step-by-step explanation:

To get the absolute maximum and minimum values of the function f(x) = 16 + 2x − x² n the given interval [0,5], we need to get the values of f(x) at the end points. The end points are 0 and 5.

at x = 0;

f(0) =  16 + 2(0) − 0²

f(0) = 16

at the other end point i.e at x = 5;

f(5) =  16 + 2(5) − 5²

f(5) = 16 + 10-25

f(5)= 26-25

f(5) = 1

The absolute minimum value is 1  and  occurs at x  = 5

The absolute maximum value is 16 and  occurs at x  = 0

5 0
3 years ago
In the drawing below, line n is a transversal that intersects two parallel lines. What is the measure of Angle 4?
4vir4ik [10]

Answer:

140°

Step-by-step explanation:

<3 = 40 because they are vertical angles

<3 +<4 = 180 because they are same side interior angles

40 + <4 = 180

Subtract 40 from each side

40-40 + <4 = 180-40

<4 = 140

4 0
3 years ago
Please Help!
Flura [38]
Let x be the length of the train.

On the basis of the observer;
Speed of the train = x/6

On the basis of the bridge;
Total distance covered by any point of the train= 350+x
Speed = (350+x)/20

Equating the two expressions of speed;
x/6 = (350+x)/20
20(x) = 6(350+x)
20x = 2100+6x
(20-6)x = 2100
14x = 2100
x= 2100/14 = 150 m
Speed = x/6 = (350+x)/20 = 150/6 = 500/20 = 25 m/s.

Therefore,
Length of train = 150 m
Speed of train = 25 m/s
8 0
3 years ago
ON YOUR OWN
vichka [17]
5 units because your starting from (-2,-2) so the last -2 will stay and the first number(-2) will go up until you hit the (,3) which will be 5 units away
6 0
2 years ago
Read 2 more answers
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