Long division: (x³ + 2) ÷ (x + 1)
<u> </u><u>x² – x + 1 </u>
x³ + 0x² + 0x + 2 | x + 1
<u>– x³ – x²</u> ⋮ ⋮
– x² + 0x ⋮
<u>+ x² + x</u><span> ⋮</span>
+ x + 2
<span> </span> <u>– x – 1</u>
+ 1
Quotient: Q(x) = x² – x – 1;
Remainder: R(x) = + 1.
I hope this helps. =)
Answer:
The length of the shadow is 48.28 feet.
Step-by-step explanation:
The flagpole at its shadow form a 46, 44, 90 triangle.
Let AB be the flagpole. AC is the shadow.
Let's use the sine law to calculate AC.

We know that the diameter of a circle is 2 times the radius.
If the radius is 0.75 meters, then the diameter must be 2 x 0.75 meters = 1.5meters
Answer:
i.e. relation between speed-distance-time is one such situation that can be modeled using graph
Step-by-step explanation:
There are many real world examples that can be modeled using graph. Graphs are represented on co-ordinate planes, so any real world example that can be represented by use of linear equation can be represented onto a graph.
One such example, is speed-distance-time relation. Uniform speed can be represented on a graph as shown in figure.
So, the equation for speed is represented by equation as follows:

So, if we take distance on y axis and time on x axis with points as (distance,time)
(0,0) ==> 
(1,2) ==> 
(2,2) ==> 
the following points 0,0.5,1 will be plotted on graph. Similarly, more values can be plotted by assuming values for distance and time.