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2 years ago

Find the area of the parallelogram below.

Mathematics

2 answers:

V125BC [204]2 years ago

8 0

The formula for finding the area of a parallelogram is Base x height

A = Bh

In this case the base (the longest side) is 8 cm and the height (distance between the obtuse angle and the base) is 5 cm

A = 8 * 5

A = 40 cm²

Hope this helps!

~Just a girl in love with Shawn Mendes

VLD [36.1K]2 years ago

6 0

Answer: 40cm²

The formula is Base × Height. We can find the area if we multiply the Base and Height.

A = Bh

As for that, the Base is the upper length, which is 8 and the height is the obtuse angle inside the parallelogram, which is 5.

Since we got our lengths, we can solve.

Remember how I said the formula is A = Bh. (Area = Base × Height)

So, we can multiply 8 by 5 to get the area.

8 times 5 will equal 40.

Hence, 40cm² is the answer.

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Find the value of X A: 2 B: 4 C: 6 D: 8

11111nata11111 [884]

Using the Pythagorean theorem:

x^2 + (x-2)^2 = (√20)^2

Simplify the right side:

x^2 + (x-2)^2 = 20

Subtract 20 from both sides:

x^2 + (x-2)^2 - 20 = 0

Factor:

(x-4)(x+2) = 0

Solve for each x:

x = 4 and x = -2

The side cant be a negative value, so the answer would be x = 4

The answer is B.

3 0

3 years ago

When studying radioactive material, a nuclear engineer found that over 365 days,

Gnom [1K]

Answer:

a) The mean number of radioactive atoms that decay per day is 81.485.

b) 0% probability that on a given day, 50 radioactive atoms decayed.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\lambda$ is the mean in the given interval.

a. Find the mean number of radioactive atoms that decayed in a day.

29,742 atoms decayed during 365 days, which means that:

$\lambda = \frac{29742}{365} = 81.485$

The mean number of radioactive atoms that decay per day is 81.485.

b. Find the probability that on a given day, 50 radioactive atoms decayed.

This is P(X = 50). So

$P(X = 50) = \frac{e^{-81.485}*(81.485)^{50}}{(50)!} = 0$

0% probability that on a given day, 50 radioactive atoms decayed.

5 0

3 years ago

A chemical company makes two brands of antifreeze. The first brand is 20% pure antifreeze, and the second brand is 70% pure anti

andre [41]

Answer:

First brand of antifreeze: 21 gallons

Second brand of antifreeze: 9 gallons

Step-by-step explanation:

Let's call A the amount of first brand of antifreeze. 20% pure antifreeze

Let's call B the amount of second brand of antifreeze. 70% pure antifreeze

The resulting mixture should have 35% pure antifreeze, and 30 gallons.

Then we know that the total amount of mixture will be:

$A + B = 30$

Then the total amount of pure antifreeze in the mixture will be:

$0.2A + 0.7B = 0.35 * 30$

$0.2A + 0.7B = 10.5$

Then we have two equations and two unknowns so we solve the system of equations. Multiply the first equation by -0.7 and add it to the second equation:

$-0.7A -0.7B = -0.7*30$

$-0.7A -0.7B = -21$

$0.2A + 0.7B = 10.5$

--------------------------------------

$-0.5A = -10.5$

$A = \frac{-10.5}{-0.5}$

$A = 21\ gallons$

We substitute the value of A into one of the two equations and solve for B.

$21 + B = 30$

$B = 9\ gallons$

3 0

3 years ago

What’s the answer ????

Temka [501]

Answer:

Answer is 4/25

Step-by-step explanation:

0.16*100 = 16 which would allow us to say 16/100

now you can divide 16 and 100 by 4 which would be

16/4 = 4 and 100/4= 25

therefore the answer is 4/25

8 0

3 years ago

Consider the two data sets. Which has the higher mean and median? What is the higher mean and median?

Klio2033 [76]

Set 1 mean - 23.625

Set 2 mean - 23.5

Set 1 median - 23.5

Set 2 median - 22.5

This shows the answer is D :)

8 0

3 years ago