The answer is <span>5, 4, 2
</span>
Among all choices we have 5, so
x = 5
x - 5 = 0
Let's divide the expression by (x - 5) using the long division:
x³ - 11x² + 38x - 40
(x - 5) * x² = x³ - 5x² Subtract
____________________________
-6x² + 38x - 40
(x - 5) * (-6x) = -6x² + 30x Subtract
____________________________
8x - 40
(x - 5) * 8 = 8x - 40 Sutract
____________________________
0
Thus: x³ - 11x² + 38x - 40 = (x - 5)(x² - 6x + 8)
Now, let's simplify x² - 6x + 8.
x² - 6x + 8 = x² - 2x - 4x + 8 =
= x² - 2*x - (4*x - 4*2) =
= x(x - 2) - 4(x - 2) =
= (x - 4)(x - 2)
Hence:
x³ - 11x² + 38x - 40 = (x - 5)(x - 4)(x - 2)
To calculate zero:
x³ - 11x² + 38x - 40 = 0
(x - 5)(x - 4)(x - 2) = 0
x - 5 = 0 or x - 4 = 0 or x - 2 = 0
x = 5 or x = 4 or x = 2
Answer:
411.38
Step-by-step explanation:
When you add 27.38 and 384 together, you get 411.38.
A parallelogram is a figure which has its <em>opposite</em> sides to be <u>equal</u> and <u>parallel</u>. The <em>missing</em> reason in the proof is:
B. Substitution Angle Angle Postulate.
A <em>parallelogram</em> is a type of quadrilateral that has its <u>opposite</u> sides to be equal and parallel. The sum of its <em>internal</em> angles is 
.
To <u>prove</u> that ∠ BAD ≅ ∠ DCB, we have:
Given parallelogram ABCD;
<BAC ≅ <ACD (alternate angle theorem)
<DAC ≅ <ACB (alternate angle theorem)
<BAC + <DAC = <BAD
Also,
<BCA + <DCA = <BCD
Therefore,
<BAD ≅ <DCB (Substitution Angle Angle Postulate)
Thus, the <u>missing</u> reason in the partial proof is:
option B. Substitution Angle Angle Postulate
A sketch is attached to this question for more clarifications.
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Answer:
Rs. 100 and Rs. 150
Step-by-step explanation:
the ratio = 2:3 => the sum = 2+3=5
Sita gets = 2/5 × 250 = 100
Ram gets = 3/5 × 250 = 150
