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avanturin [10]
3 years ago
5

If there are two real solutions to the equation x^2 + 4x + c = 0, which is a possible value of c?

Mathematics
2 answers:
kvasek [131]3 years ago
5 0
\bf \begin{array}{lcccllll}
1x^2 &+ 4x &+ c\\
\uparrow &\uparrow &\uparrow \\
a&b&c
\end{array}\qquad discriminant\implies b^2-4ac
\\ \quad \\
\textit{if the discriminant is}
\begin{cases}
positive\to &\textit{two solutions}\\
0\to &\textit{one solution}\\
negative\to &\textit{no solution}
\end{cases}

so.. check your "c" choices, to see which one gives you a positive discriminant
NikAS [45]3 years ago
5 0
C Appears To Be An Answer Choice
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Step-by-step explanation:

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Step-by-step explanation:

Let f ( x) be a polynomial with real coefficients and with a positive lending coefficient.

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b ) if c<0 and the number in the bottom row of the synthetic division alternate in sign  then f (x) has no zero less than c

As shown in the figure

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