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avanturin [10]
3 years ago
5

If there are two real solutions to the equation x^2 + 4x + c = 0, which is a possible value of c?

Mathematics
2 answers:
kvasek [131]3 years ago
5 0
\bf \begin{array}{lcccllll}
1x^2 &+ 4x &+ c\\
\uparrow &\uparrow &\uparrow \\
a&b&c
\end{array}\qquad discriminant\implies b^2-4ac
\\ \quad \\
\textit{if the discriminant is}
\begin{cases}
positive\to &\textit{two solutions}\\
0\to &\textit{one solution}\\
negative\to &\textit{no solution}
\end{cases}

so.. check your "c" choices, to see which one gives you a positive discriminant
NikAS [45]3 years ago
5 0
C Appears To Be An Answer Choice
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Step-by-step explanation:

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A taxi ride costs p40.00 for the first 500 meters and each additional 300 meters or a fraction there of adds p3.50 to the fare.u
Zarrin [17]

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According to the question,

For first 500 meters cost is  40.00 and For each additional 300 meters cost is 3.50 .

Let, the total distance of taxi ride = d meters

Now, representing the equation of taxi fare in terms of distance when distance is less than 500

taxi fare = 3.50 ×  \frac{d-500}{300}  + 40

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1 year ago
9.48 as a mixed number in simplist form
mafiozo [28]

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Step-by-step explanation:

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<em><u>948/100= 948 ÷ 4/100 ÷ 4</u></em>

<em><u>948/100= 948 ÷ 4/100 ÷ 4= 237/25</u></em>

<em><u>948/100= 948 ÷ 4/100 ÷ 4= 237/25= 9 12/25</u></em>

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