If there are two real solutions to the equation x^2 + 4x + c = 0, which is a possible value of c?

2 answers:

5 0

$\bf \begin{array}{lcccllll}
1x^2 &+ 4x &+ c\\
\uparrow &\uparrow &\uparrow \\
a&b&c
\end{array}\qquad discriminant\implies b^2-4ac
\\ \quad \\
\textit{if the discriminant is}
\begin{cases}
positive\to &\textit{two solutions}\\
0\to &\textit{one solution}\\
negative\to &\textit{no solution}
\end{cases}$

so.. check your "c" choices, to see which one gives you a positive discriminant

NikAS [45]3 years ago

5 0

C Appears To Be An Answer Choice

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