Let
be the dimensions of the rectangle. We know the equations for both area and perimeter:


So, we have the following system:

From the second equation, we can deduce

Plug this in the first equation to get

Refactor as

And solve with the usual quadratic formula to get

Both solutions are feasible, because they're both positive.
If we chose the positive solution, we have

If we choose the negative solution, we have

So, we're just swapping the role of
and
. The two dimensions of the rectangle are
and 
If these are the given choices of the above problem,
a. one side and one angle are equal.
<span>b.three sides are equal </span>
<span>c.two angles are equal </span>
<span>d. three angles are equal
Two non-right triangles are congruent when B. THREE SIDES ARE EQUAL.
Two triangles are congruent if:
1) All corresponding sides are equal (SSS)
2) A pair of corresponding sides and the included angle are equal (SAS)
3) A pair of corresponding angles and the included side are equal (ASA)
4) A pair of corresponding angles and a non-included side are equal (AAS)</span>
Answer:

Step-by-step explanation:
The width of the free play section is 9 feet. The length is 5+5, which equals 10.
The area is
×
.
9×10=90 feet square
<u>Hope this helps :-)</u>