14 more than a number u

The vertex from a quadratic function is f(x)=a(x-h)^2+k what is the vertex if each function match the function rule with the coo

MrMuchimi

Answer: (h,k)

Step-by-step explanation: remember that H is your x coordinate and should be the opposite sign of what's in the parenthesis.

7 0

4 years ago

Read 2 more answers

Please i need help ! its due today ! Class A has 10 pupils and class B has 17 pupils.

Rudiy27

Answer:

The mean score is 87

Step-by-step explanation:

79x2=158

158-71=87

6 0

2 years ago

Simplify 7x + 2y - 3x + 4y Factorise 10x - 15 Solve 5p = 3p + 8

vlada-n [284]

Answer:

1. x = -1.5y

2. 5 (2x-3)

3. p = 4

Step-by-step explanation:

1) Simplifying

7x + 2y + -3x + 4y = 0

Reorder the terms:

7x + -3x + 2y + 4y = 0

Combine like terms: 7x + -3x = 4x

4x + 2y + 4y = 0

Combine like terms: 2y + 4y = 6y

4x + 6y = 0

Solving

4x + 6y = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-6y' to each side of the equation.

4x + 6y + -6y = 0 + -6y

Combine like terms: 6y + -6y = 0

4x + 0 = 0 + -6y

4x = 0 + -6y

Remove the zero:

4x = -6y

Divide each side by '4'.

x = -1.5y

Simplifying

x = -1.5y

2)

Common factor

10x - 15

5 (2x-3)

3) Simplifying

5p = 3p + 8

Reorder the terms:

5p = 8 + 3p

Solving

5p = 8 + 3p

Solving for variable 'p'.

Move all terms containing p to the left, all other terms to the right.

Add '-3p' to each side of the equation.

5p + -3p = 8 + 3p + -3p

Combine like terms: 5p + -3p = 2p

2p = 8 + 3p + -3p

Combine like terms: 3p + -3p = 0

2p = 8 + 0

2p = 8

Divide each side by '2'.

p = 4

Simplifying

p = 4

7 0

3 years ago

Sanya has a piece of land which is in the shape of a rhombus. She wants her one daughter and one son to work on the land and pro

viva [34]

Answer:

9600 m2

Step-by-step explanation:

6 0

3 years ago

Math help Please!!!!

GalinKa [24]

Part A. What is the slope of a line that is perpendicular to a line whose equation is −2y=3x+7?

Rewrite the equation −2y=3x+7 in the form $y=-\dfrac{3}{2}x-\dfrac{7}{2}.$ Here the slope of the given line is $m_1=-\dfrac{3}{2}.$ If $m_2$ is the slope of perpendicular line, then

$m_1\cdot m_2=-1,\\ \\m_2=-\dfrac{1}{m_1}=\dfrac{2}{3}.$

Answer 1: $\dfrac{2}{3}$

Part B. The slope of the line y=−2x+3 is -2. Since $-\dfrac{3}{2}\neq -2\quad \text{and}\quad \dfrac{2}{3}\neq -2,$ then lines from part A are not parallel to line a.

Since $-2\cdot \left(-\dfrac{3}{2}\right)=3\neq -1\quad \text{and}\quad -2\cdot \dfrac{2}{3}=-\dfrac{4}{3}\neq -1,$ both lines are not perpendicular to line a.

Answer 2: Neither parallel nor perpendicular to line a

Part C. The line parallel to the line 2x+5y=10 has the equation 2x+5y=b. This line passes through the point (5,-4), then

2·5+5·(-4)=b,

10-20=b,

b=-10.

Answer 3: 2x+5y=-10.

Part D. The slope of the line $y=\dfrac{x}{4}+5$ is $\dfrac{1}{4}.$ Then the slope of perpendicular line is -4 and the equation of the perpendicular line is y=-4x+b. This line passes through the point (2,7), then