The vertex from a quadratic function is f(x)=a(x-h)^2+k what is the vertex if each function match the function rule with the coo
2 answers:
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Answer: The second option (160 cm)
Step-by-step explanation:
1. You can obtain the perimeter of a quadrilateral by adding the lenghts of the sides.
2. You know that the ratio of the side lengths is 3:3:5:8 and the perimeter is 380 centimeters.
3. Therefore, you can write the following expression, where x is an integer:
4. Solve for x:
5. Therefore, the longest side is:
(160 cm)
Answer:
maximum: y = 1
minimum: y = 0.
Step-by-step explanation:
Here we have the function:
y = f(x) = √(1 + x^2 - 2x)
we want to find the minimum and maximum in the segment [0, 1]
First, we evaluate in the endpoints, which are 0 and 1.
f(0) =√(1 + 0^2 - 2*0) = 1
f(1) = √(1 + 1^2 - 2*1) = 0
Now let's look at the critical points (the zeros of the first derivate)
To derivate our function, we can use the chain rule:
f(x) = h(g(x))
then
f'(x) = h'(g(x))*g(x)
Here we can define:
h(x) = √x
g(x) = 1 + x^2 - 2x
Then:
f(x) = h(g(x))
f'(x) = 1/2*( 1 + x^2 - 2x)*(2x - 2)
f'(x) = (1 + x^2 - 2x)*(x - 1)
f'(x) = x^3 - 3x^2 + x - 1
this function does not have any zero in the segment [0, 1] (you can look it in the image below)
Thus, the function does not have critical points in the segment.
Then the maximum and minimum are given by the endpoints.
The maximum is 1 (when x = 0)
the minimum is 0 (when x = 1)
