If anything is in parentheses do that first, however if there isn’t you always do exponents next so evaluate 6 squared
Hope this helps!!
Answer: -7744.
Step-by-step explanation: ...
Basically, you just move every individual point up, down, left, or right by the amount indicated.
For example, point G is graphed on the point (-3, -1). Moving it right 5 and up 1 will give you G’, which is (2,0)
T is graphed on the point (-1, -1). Moving it right 5 and up 1 will give you T’, which is (4,0)
B is graphed on the point (-3, -5). Moving it right 5 and up 1 will give you B’, which is
(2,4)
Range: maximum - minimum
IQR: third quartile - first quartile
median: middle number once all numbers are put in numerical order
Answer:
(p ∧ q)’ ≡ p’ ∨ q’
Step-by-step explanation:
First, p and q have just four (4) possibilities, p∧q is true (t) when p and q are both t.
p ∧ q
t t t
t f f
f f t
f f f
next step is getting the opposite
(p∧q)'
<em>f</em>
<em> t</em>
<em> t</em>
<em> t</em>
Then we get p' V q', V is true (t) when the first or the second is true.
p' V q'
f <em>f</em> f
f <em>t</em> t
t <em>t</em> f
t <em>t</em> t
Let's compare them, ≡ is true if the first is equal to the second one.
(p∧q)' ≡ (p' V q')
<em>f f </em>
<em> t t</em>
<em> t t</em>
<em> t t</em>
Both are true, so
(p ∧ q)’ ≡ p’ ∨ q’
