What is the solution to the system?

1 answer:

5 0

2x + y - z = -3 .....multiply by 2
5x - 2y + 2z = 24
-----------------
4x + 2y - 2z = -6 (result of multiplying by 2)
5x - 2y + 2z = 24
----------------add
9x = 18
x = 18/9
x = 2

3x - z = 5
3(2) - z = 5
6 - z = 5
6 - 5 = z
1 = z

2x + y - z = -3
2(2) + y - 1 = -3
4 + y - 1 = -3
y + 3 = -3
y = -3 - 3
y = -6

solution is : (2.-6,1)

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A dog and a cat are 200 meters apart when they see each other. The dog can run at a speed of 30 meter per second, while the cat

LenKa [72]

Answer:

They'll meet after 200 meters , if they simultaneously start running towards each other.

Step-by-step explanation:

Let x =distance travelled by dog and 200-x be the distance travelled by cat. Inorder to meet, the sum of their travelled distances shall be equal to 200 meters as they are far apart by 200 meters.

Dog: Distance =Speed x time: x=30t

Cat: Distance = 200-x

=24t

The sum of their distance travelled shall be 200 meters: 30t+ 24t= 200;54t=200;t=200/54=3.7secs

So they will meet after 3.7 seconds

To check:

Distance travelled by dog :x=30(3.7)

=111.11 meters

Distance travelled by cat: 24t=24(3.7)

=88.89 meters

Therefore since they are travelling towards each other and their distance apart is 200 meters, after 3.7 seconds they will meet because dog travelled 111.11 meters and cat travelled 88.89 meters and they covered already 200 meters as the sum of 111.11+ 88.89

=200 meters

6 0

1 year ago

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natali 33 [55]

Answer:

$the \: expession \: is \: equivalent \: to \: 2$