Answer:
The first plane is moving at 295 mph and the second plane is moving at 355mph.
Step-by-step explanation:
In order to find the speed of each plane we first need to know the relative speed between them, since they are flying in oposite directions their relative speed is the sum of their individual speeds. In this case the speed of the first plane will be "x" and the second plane will be "y". So we have:
x = y - 60
relative speed = x + y = (y - 60) + y = 2*y - 60
We can now apply the formula for average speed in order to solve for "y", we have:
average speed = distance/time
average speed = 1625/2.5 = 650 mph
In this case the average speed is equal to their relative speed, so we have:
2*y - 60 = 650
2*y = 650 + 60
2*y = 710
y = 710/2 = 355 mph
We can now solve for "x", we have:
x = 355 - 60 = 295 mph
The first plane is moving at 295 mph and the second plane is moving at 355mph.
7 * 0.5 + 3 * 0.8 = 3.5 + 2.4 = 5.9
<span>5.9/10 X 100 = 59%
</span><span>59% concentration of new mixture</span>
Answer:
he gets 11 per week
Step-by-step explanation:
mark brainly pls
Answer: 441
Step-by-step explanation:
![7*(6+2)^2-3^2](https://tex.z-dn.net/?f=7%2A%286%2B2%29%5E2-3%5E2)
![7*8^2-3^2](https://tex.z-dn.net/?f=7%2A8%5E2-3%5E2)
![7*64-9](https://tex.z-dn.net/?f=7%2A64-9)
![448-9](https://tex.z-dn.net/?f=448-9)
441
Answer:
5. f(x) = 10,000 (1.5)^x
Step-by-step explanation:
We would have to multiply the original amount by 1.50^x because the initial amount would be 1, and 50% increase would be .5 so 1.5 and you raise it to the number of years to show the total increase.
Let's test it.
Initial:
10,000
After 1 year
10,000 + (.5*10000)
10,000 + 5000 = 15,000
After 2 years
15,000 + (.5*15000)
15,000 + 7500 = 22,500
Let's try our equation.
f(x) = 10,000 (1.5)^x
x = 2
10,000(1.5)^2
10,000(2.25) = 22,500
The same!