Which decimal is larger 36.36 or 36.63 PLEASE HELP!!

1 answer:

7 0

36.36 is thirty-six and thirty-six hundredths.
36.63 is thirty-six and sixty-three hundredths.

The whole parts are the same. They are both 36.
The decimal parts are 0.63 and 0.36.
Sixty-three hundredths is greater than thirty-six hundredths.
Since 0.63 is greater than 0.36, 36.63 is greater.

You might be interested in

Amit found and labeled the areas of each of the faces of Which area calculation did Amit calculate incorrectly?

Gelneren [198K]

Answer:

Step-by-step explanation: I got it right

5 0

3 years ago

Read 2 more answers

Megan purchased a new gadget for her technology hobby. She plans to sell it sometime in the future, however, its value depreciat

Inga [223]

M represents the month because the value is decreasing every month.

Hope this helps :)

5 0

3 years ago

Read 2 more answers

Calculus 3 chapter 16

o-na [289]

Evaluate $\vec F$ at $\vec r$ :

$\vec F(x,y,z) = x\,\vec\imath + y\,\vec\jmath + xy\,\vec k \\\\ \implies \vec F(\vec r(t)) = \vec F(\cos(t), \sin(t), t) = \cos(t)\,\vec\imath + \sin(t)\,\vec\jmath + \sin(t)\cos(t)\,\vec k$

Compute the line element $d\vec r$ :

$d\vec r = \dfrac{d\vec r}{dt} dt = \left(-\sin(t)\,\vec\imath+\cos(t)\,\vec\jmath+\vec k\bigg) \, dt$

Simplifying the integrand, we have

$\vec F\cdot d\vec r = \bigg(-\cos(t)\sin(t) + \sin(t)\cos(t) + \sin(t)\cos(t)\bigg) \, dt \\ ~~~~~~~~= \sin(t)\cos(t) \, dt \\\\ ~~~~~~~~= \dfrac12 \sin(2t) \, dt$

Then the line integral evaluates to

$\displaystyle \int_C \vec F\cdot d\vec r = \int_0^\pi \frac12\sin(2t)\,dt \\\\ ~~~~~~~~ = -\frac14\cos(2t) \bigg|_{t=0}^{t=\pi} \\\\ ~~~~~~~~ = -\frac14(\cos(2\pi)-\cos(0)) = \boxed{0}$