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4 years ago

The formula, P=V^2/R,gives the relationship between resistance (R), voltage (V) and power (P). Solve the formula for Voltage

1 answer:

riadik2000 [5.3K]4 years ago

8 0

Start by multiplying both sides by R to isolate V².
V² = P·R

Now, take the square root of both sides to get V.

V = √PR

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4.. Please help. Is DE←→ perpendicular to FG←→? Why or why not?

olya-2409 [2.1K]

Given:

DE contains the points D(1, -2) and E(3, 4).

FG contains the points F(-1, 2) and G(4, 0).

To find:

Is DE perpendicular to FG.

Solution:

Slope of DE:

$$m=\frac{y_2-y_1}{x_2-x_1}$

Here $x_1=1, y_1=-2, x_2=3, y_2=4$

$$m=\frac{4-(-2)}{3-1}$

$$m=\frac{6}{2}$

m = 3

Slope of FG:

$$m=\frac{y_2-y_1}{x_2-x_1}$

Here $x_1=-1, y_1=2, x_2=4, y_2=0$

$$m=\frac{0-2}{4-(-1)}$

$$m=\frac{-2}{4+1}$

$$m=\frac{-2}{5}$

<em>Two lines are perpendicular if product their slopes are -1.</em>

Slope of DE × Slope of FG

$$=3\times \frac{-2}{5}$

$$= \frac{-6}{5}$

≠ -1

The solution is no, because the product of the slopes is not -1.

3 0

3 years ago

Read 2 more answers

Hi another math question please help:)

Mama L [17]

Answer:

1). Yes

2). Yes

3). No

Step-by-step explanation:

1). y = 3

We can rewrite this equation in the slope-intercept form as,

y = 0.x + 3

Here, slope = 0

y-intercept = 3

Therefore, it's a linear relation.

YES.

2). 2x - 5y = 10

5y = 2x - 10

y = $\frac{2}{5}x-2$

Therefor, it's a linear function.

YES

3). y = x(x + 3)

y =x² + 3x

Since, this equation is a quadratic equation,

It's not a linear function.

5 0

3 years ago

If x= 3 and y=2, evaluate the following<br>expressions <br>io 2xt 3y

kirza4 [7]

helli I kaiahaahajkasn

Step-by-step explanation:

helli I kaiahaahajkasn

7 0

4 years ago

Read 2 more answers

Taylor charges $15 for the first hour of dog walking and $10 for each additional hour or fraction of an hour. The rates that Luc

svetoff [14.1K]

Answer:

Taylor will charge more by $15

Step-by-step explanation:

Given

Taylor

First Hour = $15

Hourly Rate = $10

Lucy:

$f(x) = \left \{ {{20x,\ 0 \le \ x \ \le 2} \atop {10x, x>2}} \right.$

For a dog walk of 2.5 hours.

Taylor's charges is:

$Charges = First\ Hour + Hourly\ Rate * 2.5$

$Charges = \$15 + \$10 * 2.5$

$Charges = \$15 + \$25$

$Charges = \$40$

Lucy's charges is:

Here, we consider

$f(x) = 10x$ Because $x > 2$

i.e 2.5 > 2

So, Lucy's charges is:

$Charges = 10 * \$2.5$

$Charges = \$25$

By comparison;

Taylor will charge more by $15

The difference is calculated by:

$Difference = \$40 - \$25$

$Difference = \$15$

4 0

3 years ago

4400 dollars is placed in an account with an annual interest rate of 8.25%. How much will be in the account after 22 years, to t

Ulleksa [173]

$\bf \qquad \textit{Simple Interest Earned Amount}\\\\
A=P(1+rt)\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$4400\\
r=rate\to 8.25\%\to \frac{8.25}{100}\to &0.0825\\
t=years\to &22
\end{cases}
\\\\\\
A=4400(1+0.0825\cdot 22)$

and surely you know how much that is.

3 0

4 years ago

Read 2 more answers