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kodGreya [7K]
3 years ago
13

If JL= 54, what is the value of x? x

Mathematics
1 answer:
kicyunya [14]3 years ago
7 0

Answer:

x=2

Step-by-step explanation:

(8x+11)+(14x-1)=54=> 22x +10=54=>22x=44=>x=2

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The sum of 69,75,81,87,93,99 is 504.0.
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If the measure of angle 1 is 68°, what is the measure of angle 5?
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68 degrees as well, because the angles are corresponding.
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The equation Ax+By=10 goes through the coordinates (6,5) and (-2,-5).What are the values of A and B
wolverine [178]

Given:

The equation Ax+By=10 goes through the coordinates (6,5) and (-2,-5).

To find:

The values of A and B.

Solution:

We have,

Ax+By=10

It goes through the coordinates (6,5) and (-2,-5). It means these points will satisfy the equation.

A(6)+B(5)=10

6A+5B=10       ...(i)

A(-2)+B(-5)=10

-2A-5B=10       ...(ii)

Adding (i) and (ii), we get

(6A+5B)+(-2A-5B)=10+10

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Divide both sides by 4.

A=5

Put A=5 in (i), we get

6(5)+5B=10

30+5B=10

5B=10-30

5B=-20

Divide both sides by 5.

B=-4

Therefore, the values of A and B are 5 and -4 respectively.

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2 years ago
Susie has a bag with 8 hair pins, 6 pencils, 3 snacks, and 5 books. What is the ratio of books to pencils?
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Answer:

D) 5/8

Step-by-step explanation:

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3 years ago
A triangle is formed from the points L(-3, 6), N(3, 2) and P(1, -8). Find the equation of the following lines:
Dima020 [189]

Answer:

Part A) y=\frac{3}{4}x-\frac{1}{4}  

Part B)  y=\frac{2}{7}x-\frac{5}{7}

Part C) y=\frac{2}{7}x+\frac{8}{7}

see the attached figure to better understand the problem

Step-by-step explanation:

we have

points L(-3, 6), N(3, 2) and P(1, -8)

Part A) Find the equation of the  median from N

we Know that

The median passes through point N to midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

we have

L(-3, 6) and P(1, -8)

substitute the values

M(\frac{-3+1}{2},\frac{6-8}{2})

M(-1,-1)

step 2

Find the slope of the segment NM

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}  

we have

N(3, 2) and M(-1,-1)

substitute the values

m=\frac{-1-2}{-1-3}

m=\frac{-3}{-4}

m=\frac{3}{4}

step 3

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=\frac{3}{4}

point\ N(3, 2)

substitute

y-2=\frac{3}{4}(x-3)

step 4

Convert to slope intercept form

Isolate the variable y

y-2=\frac{3}{4}x-\frac{9}{4}

y=\frac{3}{4}x-\frac{9}{4}+2

y=\frac{3}{4}x-\frac{1}{4}  

Part B) Find the equation of the  right bisector of LP

we Know that

The right bisector is perpendicular to LP and passes through midpoint segment LP

step 1

Find the midpoint segment LP

The formula to calculate the midpoint between two points is equal to

M(\frac{x1+x2}{2},\frac{y1+y2}{2})

we have

L(-3, 6) and P(1, -8)

substitute the values

M(\frac{-3+1}{2},\frac{6-8}{2})

M(-1,-1)

step 2

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}  

we have

L(-3, 6) and P(1, -8)

substitute the values

m=\frac{-8-6}{1+3}

m=\frac{-14}{4}

m=-\frac{14}{4}

m=-\frac{7}{2}

step 3

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

m_1*m_2=-1

we have

m_1=-\frac{7}{2}

so

m_2=\frac{2}{7}

step 4

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=\frac{2}{7}

point\ M(-1,-1) ----> midpoint LP

substitute

y+1=\frac{2}{7}(x+1)

step 5

Convert to slope intercept form

Isolate the variable y

y+1=\frac{2}{7}x+\frac{2}{7}

y=\frac{2}{7}x+\frac{2}{7}-1

y=\frac{2}{7}x-\frac{5}{7}

Part C) Find the equation of the altitude from N

we Know that

The altitude is perpendicular to LP and passes through point N

step 1

Find the slope of the segment LP

The formula to calculate the slope between two points is equal to

m=\frac{y2-y1}{x2-x1}  

we have

L(-3, 6) and P(1, -8)

substitute the values

m=\frac{-8-6}{1+3}

m=\frac{-14}{4}

m=-\frac{14}{4}

m=-\frac{7}{2}

step 2

Find the slope of the perpendicular line to segment LP

Remember that

If two lines are perpendicular, then their slopes are opposite reciprocal (the product of their slopes is equal to -1)

m_1*m_2=-1

we have

m_1=-\frac{7}{2}

so

m_2=\frac{2}{7}

step 3

Find the equation of the line in point slope form

y-y1=m(x-x1)

we have

m=\frac{2}{7}

point\ N(3,2)

substitute

y-2=\frac{2}{7}(x-3)

step 4

Convert to slope intercept form

Isolate the variable y

y-2=\frac{2}{7}x-\frac{6}{7}

y=\frac{2}{7}x-\frac{6}{7}+2

y=\frac{2}{7}x+\frac{8}{7}

7 0
3 years ago
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