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kodGreya [7K]
3 years ago
13

If JL= 54, what is the value of x? x

Mathematics
1 answer:
kicyunya [14]3 years ago
7 0

Answer:

x=2

Step-by-step explanation:

(8x+11)+(14x-1)=54=> 22x +10=54=>22x=44=>x=2

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Evealute the expression when m= -2 m^2+9m+3
Volgvan

Step-by-step explanation:

m=-2

m^2+9m+3

substitute-2 in m

-2^2+9(-2)+3

= -19

8 0
2 years ago
Can you help me find the side??? It's trigonometry!!
olganol [36]

Answer: 5.6

===================================

Work Shown:

cos(angle) = adjacent/hypotenuse

cos(B) = AB/BC

cos(62) = AB/12

12*cos(62) = AB

AB = 12*cos(62)

AB = 5.63365875

AB = 5.6

8 0
3 years ago
Which is an x-intercept of the continuous function in the
Paladinen [302]

Answer:

(-1, 0), (2, 0), (3, 0)

Step-by-step explanation:

x-intercept of a line is defined by a point where y = 0.

So the point in the form of (x, 0) will be the x-intercept of the given continuous function.

From the table attached,

For x = -1, f(-1) = 0

For x = 2, f(2) = 0

For x = 3, f(3) = 0

Points (-1, 0), (2, 0) and (3, 0) are the x-intercepts of the continuous function f(x).

5 0
3 years ago
Find m/ GJI<br> a. 15<br> b. 75<br> c.100<br> d. 105
sertanlavr [38]
M<GJI=(x+60)°=?

We need to find x. The angle GJI and FJH are opposite by the the vertex, then they must be congruents:
(x+60)°=(5x)°
x+60=5x
Solving for x
x+60-x=5x-x
60=4x
60/4=4x/4
15=x
x=15

Replacing x by 15 in m<GJI:
m<GJI=(x+60)°=(15+60)°→m<GJI=75°

Answer: Option b. 75
3 0
3 years ago
I need help with this problem , GEOMETRY
34kurt

k:\ y=m_1x+b_1\\l:\ y=m_2x+b_2\\\\k\ ||\ l\iff m_1=m_2\\\\k\ \perp\ l\iff m_1m_2=-1

1.\\(-6,\ 1),\ (0,\ -2)\\\\m_1=\dfrac{-2-1}{0-(-6)}=\dfrac{-3}{6}=-\dfrac{1}{2}\\\\(0,\ 3),\ (4,\ 1)\\\\m_2=\dfrac{1-3}{4-0}=\dfrac{-2}{4}=-\dfrac{1}{2}\\\\m_1=m_2\\\\Answer:\ Parallel


(-4,\ 0),\ (2,\ 4)\\\\m_1=\dfrac{4-0}{2-(-4)}=\dfrac{4}{6}=\dfrac{2}{3}\\\\(-3,\ 4),\ (1,\ -2)\\\\m_2=\dfrac{-2-4}{1-(-3)}=\dfrac{-6}{4}=-\dfrac{3}{2}\\\\m_1m_2=\dfrac{2}{3}\cdot\left(-\dfrac{3}{2}\right)=-1\\\\Answer:\ Perpendicular

5 0
2 years ago
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