Ask question

Ask question

All categories

Marizza181 [45]

3 years ago

5

How much meters per second did the cyclist travel from 8 a.M. To 10 a.M? (*TIP: 2 hours = 7200 seconds, 2 km= 2000 m). Give the

formula used, show your working and round off your answer to two decimal places. Don't forget the unit! *

1 answer:

Mice21 [21]3 years ago

4 0

Answer:

0.28 meters per second.

Step-by-step explanation:

We have that the speed formula is as follows:

v = d / t

In this case they tell us that the distance is 2 km the equivalent of 2000 meters and the time is 2 hours the equivalent of 7200 seconds, we replace and we are left with:

v = 2000/7200 = 0.28

Therefore it ran 0.28 meters per second.

You might be interested in

-47+-58 order of operations

kicyunya [14]

Answer: -105

Step-by-step explanation:

:)

7 0

3 years ago

Read 2 more answers

How is the process of dividing integers similar to the process of multiplying integers? Select your answer from the drop drown m

vladimir2022 [97]

Answer:

In both cases, if the signs of the initial numbers are the same, the answer will be positive. If the signs are different, the answer will be negative

Step-by-step explanation:

Required

Signs of results of multiplication and division

If two non-zero numbers have the same sign, and they are multiplied together, the end result will be positive.

For instance:

$2 * 4 = 8$

2 and 4 are positive; so, 8 is positive

$-2 * -4 = 8$

-2 and -4 are negative; so, 8 is positive

If two non-zero numbers have different signs, and they are multiplied together, the end result will be negative.

For instance:

$-2 * 4 = -8$

-2 is negative, and 4 is positive; so, -8 is negative

$2 * -4 = -8$

2 is positive, and -4 is negative; so, -8 is negative

5 0

2 years ago

A survey was conducted in the United Kingdom, where respondents were asked if they had a university degree. One question asked,

katovenus [111]

Answer:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

Step-by-step explanation:

Data given and notation

$X_{1}=45$ represent the number of correct answers for university degree holders

$X_{2}=57$ represent the number of correct answers for university non-degree holders

$n_{1}=373$ sample 1 selected

$n_{2}=639$ sample 2 selected

$p_{1}=\frac{45}{373}=0.121$ represent the proportion of correct answers for university degree holders

$p_{2}=\frac{57}{639}=0.0892$ represent the proportion of correct answers for university non-degree holders

z would represent the statistic (variable of interest)

$p_v$ represent the value for the test (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the proportions are different between the two groups, the system of hypothesis would be:

Null hypothesis: $p_{1} = p_{2}$

Alternative hypothesis: $p_{1} \neq p_{2}$

We need to apply a z test to compare proportions, and the statistic is given by:

$z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}$ (1)

Where $\hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{45+57}{373+639}=0.101$

Calculate the statistic

Replacing in formula (1) the values obtained we got this:

$z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620$

Statistical decision

For this case we don't have a significance level provided $\alpha$ , but we can calculate the p value for this test.

Since is a one side test the p value would be:

$p_v =2*P(Z>1.620)=0.105$

If we compare the p value and using any significance level for example $\alpha=0.05$ always $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

7 0

3 years ago

The farmer down the street has an orchard with both orange and grapefruit trees. Over the weekend, she collected 49 oranges and

jeka57 [31]

Answer:

30 baskets

Step-by-step explanation:

Find the gfc of 150 and 240, you'll find that it is 30

6 0

3 years ago

The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.

Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If $Z \leq -2$ or $Z \geq 2$ , the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

$\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1$

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{19 - 22}{1}$

$Z = -3$

$Z = -3 \leq -2$ , so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0

2 years ago