The driver of a taxi charges $2 every minute plus a pickup fee of $3.

1 answer:

3 0

Hey there,

To solve this first they want an expression.

An expression is basically a equation without an answer. To sort of create an outline to help you solve the question.

Lets look at what we are given:

2 dollars a minute in the taxi.

Plus a 3 dollar pickup fee

And they are asking for us to first create a expression.

If M = the minutes in the taxi ride our expression can be:

2m + 3

Because 2 dollars per minute times the amount of minutes in the taxi ride (M) plus the 3 dollar ride fee is what we need to find.

Now lets figure out how to solve C.

We already have an expression all we need to do is replace the amount of minutes variable (M) with the new amount of minutes 18!

So our new equation is:

(2 x 18) + 3

For the 2 dollars per minute, times the amount of minutes in the drive was. And finally adding on the drive fee of 3 dollars.

Solving that we get 39 dollars in total for ride.

I do hope this helps!
Brainliest is always appreciated if you feel its deserved!

You might be interested in

The directrix of a parabola is y=−4y=−4 . The focus of the parabola is (−2,−2)(−2,−2) .

Dennis_Churaev [7]

Because the focus is (-2,-2) and the directrix is y = -4, the vertex is (-2,-3).

Consider an arbitrary point (x,y) on the parabola.
The square of the distance between the focus and P is
(y+2)² + (x+2)²
The square of the distance from the point to the directrix is
(y+4)²

Therefore
(y+4)² = (y+2)² + (x+2)²
y² + 8y + 16 = y² + 4y + 4 + (x+2)²
4y = (x+2)² - 12
y = (1/4)(x+2)² - 3

Answer: $y= \frac{1}{4} (x+2)^{2} - 3$

5 0

3 years ago

We have been asked to investigate two flights, AA flight and U A flight. Both flights are at 33,000 feet, and the flight paths i

Varvara68 [4.7K]

Answer:

Both flights approach each other at a speed of 624.70 Knots. The FAA minimum separation is not violated as both airplanes are 7.26 Nautical miles away from each other at the time when one of the flights( flight AA) passes through Frada Heights.

Step-by-step explanation:

To solve this kind of problem, the knowledge of concept of relative velocity is needed as the first question requested how fast the flights were approaching each other. To find the minimum distance between both flights, the closest point of approach between both flights should be taken into consideration which was Frada heights. Flight AA passes through Frada Heights in a shorter time of 0.079 hours. This is the time at which both flights approach each other the closest and so the minimum distance (separation) between them. This was calculated to be 7.26NM which is greater than the FAA's minimum this requirement for flight was not violated.

Detailed calculation steps can be found in the attachment below.