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Mariulka [41]
3 years ago
14

Find the height of the cone if the volume is 400pi in.^3 and the radius is 20 in

Mathematics
1 answer:
irga5000 [103]3 years ago
7 0

Answer:

The height is 3

Step-by-step explanation:

The formula to find the volume is pi r^2 h/3

So we change the formula: 400pi is 1256.64 rounded

Divide 1256.64 by pi 20^2 and you get 3

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LenKa [72]

THe answer is 36 BOI

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3 years ago
Brad owns a successful corporation that has a substantial earnings and profits. During the year, the following payments were mad
Bad White [126]

Answer:

That's great for Brad, wait are you talking about the Brad from clash royale? if so im impressed

Step-by-step explanation:

3 0
3 years ago
Gary is 3 years older than twice the age of His sister Elena which shows an equation for this situation
Lynna [10]

Answer: G = 2E + 3

<u>Step-by-step explanation:</u>

Let E represent Elena's age.

Then Gary(G) is two times Elena(E) plus 3 --> G = 2E + 3

8 0
3 years ago
In 2009, a school population was 1,700. By 2017 the population had grown to 2,500. Assume the population is changing linearly. W
qaws [65]

Answer:

100

Step-by-step explanation:

The population is changing linearly. This means that the population is increasing by a particular value n every year.

From 2009 to 2017, there are 8 increases and so, the population increases by 8n.

The population increased from 1700 to 2500. Therefore, the population increase is:

2500 - 1700 = 800

This implies that:

8n = 800

=> n = 800/8 = 100

The average population growth per year is 100.

4 0
3 years ago
Find the area of a plane figure bounded by lines
natulia [17]

Answer: 4.5

<u>Step-by-step explanation:</u>

First, find the points of intersection by solving the system.

y = x² + 2x + 4

y = x + 6

Solve by substitution:

x² + 2x + 4 = x + 6   ⇒   x² + x - 2 = 0   ⇒   (x + 2)(x - 1) = 0   ⇒   x = -2, x = 1

Now, integrate from x = -2 to x = 1

\int\limits^1_2 {(x+6)-(x^{2}+2x+4) } \,    <em>the bottom of the integral is -2 </em>

= \int\limits^1_2 {x+6-x^{2}-2x-4 } \,

= \int\limits^1_2 {-x^{2}-x+2 } \,  

= \frac{-x^{3}}{3} - \frac{x^{2}}{2}+2x\int\limits^1_2 {} \,

= (\frac{-1^{3}}{3} - \frac{1^{2}}{2}+2(1)) - (\frac{-(-2)^{3}}{3} - \frac{(-2)^{2}}{2}+2(-2))

= (\frac{-1}{3} - \frac{1}{2} +2) - (\frac{8}{3} -\frac{4}{2} -4)

= \frac{-9}{3} + \frac{3}{2} +6

= -3 + 1.5 + 6

= 4.5


3 0
3 years ago
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