Answer:
She spent 142.65 for baskets, 252.50 for flowers and 185 * 0.07 or 12.95 for ribbons for a total outlay of 408.10. Since she made 30 baskets, that is 408.10/30 = 13.60 1/3 per basket.
If she sold all 30 for 25.99 each, that is 779.70 for a profit of 361.60
Step-by-step explanation:
:)
Step by step answer by answer choice by choice
Answer:
2
Step-by-step explanation:
because it goes by 2 which is proportional
For a quadratic equation ax² + bx + c = 0
Both boats start from (-8, 1)
Vertex of first boat = (1, 10)
Vertex of second boat = (0, -7)
1st boat has common points (-8, 1) and (1, 10)
2nd boat has common points (-8, 1) and (0, -7)
Let the different quadratic equations for both boats be:
y₁ = a₁x² + b₁x + c₁ and y₂ = a₂x² + b₂x + c₂
So for 1st equation.
y₁ = a₁x² + b₁x + c₁ for (-8, 1)
1 = a*(-8)² + b*(-8) + c
1 = 64a₁ - 8b₁ + c₁
64a₁ - 8b₁ + c₁ = 1................(a)
For point (1, 10)
y₁ = a₁x² + b₁x + c₁ for (1, 10)
10 = a₁*(1)² + b₁*(1) + c₁
10 = a₁ + b₁ + c₁
a₁ + b₁ + c₁ = 10................(b)
So for 2nd equation.
y₂ = a₂x² + b₂x + c₂ for (-8, 1)
1 = a₂*(-8)² + b₂*(-8) + c₂
1 = 64a₂ - 8b₂ + c₂
64a₂ - 8b₂ + c₂ = 1...............(c)
for second point (0, -7)
-7 = a₂*(0)² + b₂*(0) + c₂
-7 = 0 - 0 + c₂
c₂ = -7 .......................(d)
So system of equations are:
64a₁ - 8b₁ + c₁ = 1................(a)
a₁ + b₁ + c₁ = 10......................(b)
64a₂ - 8b₂ + c₂ = 1 ...............(c)
c₂ = -7 .......................(d)
So these are the systems of equations. When y₁ = a₁x² + b₁x + c₁ and y₂ = a₂x² + b₂x + c₂ are solved and there is a solution other than the first initial point of (-8, 1) then it means the paths crossed and if there no other solution than (-8, 1) it means their paths did not cross.
