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Anuta_ua [19.1K]
2 years ago
15

Find the 11th term of the geometric sequence 10, 20, 40, ...10,20,40,

Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
8 0

11th term is 10240

Step-by-step explanation:

  • Step 1: Given the sequence 10,20,40. So a(1) = 10, common ration, r = 20/10 = 2 Find the 11th term using the nth term formula, a(n) = ar^n-1

⇒ a(11) = 10 × 2^10 = 10 × 1024 = 10240

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Yeah. I need help with this
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Answer:

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Step-by-step explanation:

well if you take 35x, which is 35 times whatever, + 70, you get y. so the first one is 35(1) + 70 = 105.

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35 x 1 + 70 = 105

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7 0
2 years ago
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A right triangle has one side that measures 4in. The angle opposite that side measures 80 degrees. What is the length of the hyp
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Hello from MrBillDoesMath!

Answer:

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Discussion:

From the triangle, not drawn too accurately  (see attachment)


sin(80) = side opposite /hypotenuse   =>

sin (80) =  4/c            =>       multiply both sides by "c"

c sin(80) = 4/c * c      =>      

c sin(80) = 4               =>      divide both sides by sin(80)

c = 4/sin(80)

and 4/sin(80) is approximately 4.06


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6 0
3 years ago
What ratios are equivalent to 5/9
NNADVOKAT [17]

Answer:

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Step-by-step explanation:

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Answer:

H_1 : \mu  > 24.5

Step-by-step explanation:

From the given information:

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Answer:

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Step-by-step explanation:

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