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Anuta_ua [19.1K]
3 years ago
15

Find the 11th term of the geometric sequence 10, 20, 40, ...10,20,40,

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
8 0

11th term is 10240

Step-by-step explanation:

  • Step 1: Given the sequence 10,20,40. So a(1) = 10, common ration, r = 20/10 = 2 Find the 11th term using the nth term formula, a(n) = ar^n-1

⇒ a(11) = 10 × 2^10 = 10 × 1024 = 10240

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Because I've gone ahead with trying to parameterize S directly and learned the hard way that the resulting integral is large and annoying to work with, I'll propose a less direct approach.

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\displaystyle\iint_D\vec F\cdot\mathrm d\vec S=\int_0^{2\pi}\int_0^9\vec F(x(u,v),y(u,v),z(u,v))\cdot(\vec s_u\times\vec s_v)\,\mathrm du\,\mathrm dv

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\implies\displaystyle\iint_S\vec F\cdot\mathrm d\vec S=\boxed{0}

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