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3 years ago

X² - 4

Mathematics

1 answer:

emmainna [20.7K]3 years ago

8 0

Yes so he shows this by also doing what is called the flow. After this it is complete

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Sam decided to go to the amusement with his sister. He paid $10 for parking and $12.50 per ticket. Determine the y-intercept. Wr

denis-greek [22]

Answer: (0,10)

Step-by-step explanation: y=mx+b

y=12.5x+10

0=12.5x+10

10 is y because its on the outside

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2 years ago

One side of a right triangle has a length of 12 feet. Which of the following could be lengths for the two other sides of the rig

Elodia [21]

Answer:

Step-by-step explanation:

Apply the Pythagorean Theorem to determine whether or not the given triplets represent right triangles or not:

I. 5 feet and 13 feet: 5^2 + 12^2 = 13^2 is TRUE

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III. 2, 10, 12^2: 2 + 10 do NOT add up to 144. FALSE

Answer B is correct

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2 years ago

Choose the best graph that represents the linear equation: -2y = x + 6 Graph A On a coordinate plane, a line goes through (negat

Aleksandr-060686 [28]

Answer:

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Step-by-step explanation:

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2 years ago

A bakery sells 12 cupcakes for $10. A Super Market sells 10 cupcakes for $8. Which store is cheaper per cupcake? *

Fantom [35]

Answer:

Step-by-step explanation:

hope this help

8 0

2 years ago

Read 2 more answers

Here are the endpoints of the segments BC, FG, and JK.<br> B, −67

yulyashka [42]

$~~~~~~~~~~~~\textit{distance between 2 points} \\\\ B(\stackrel{x_1}{-6}~,~\stackrel{y_1}{7})\qquad C(\stackrel{x_2}{-4}~,~\stackrel{y_2}{4})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ BC=\sqrt{[-4 - (-6)]^2 + [4 - 7]^2}\implies BC=\sqrt{(-4+6)^2+(-3)^2} \\\\\\ BC=\sqrt{2^2+(-3)^2}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points}$

$F(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad G(\stackrel{x_2}{1}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ FG=\sqrt{[1 - (-2)]^2 + [-2 - (-4)]^2}\implies FG=\sqrt{(1+2)^2+(-2+4)^2} \\\\\\ FG=\sqrt{9+4}\implies \boxed{FG=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ ~~~~~~~~~~~~\textit{distance between 2 points} \\\\ J(\stackrel{x_1}{4}~,~\stackrel{y_1}{2})\qquad K(\stackrel{x_2}{5}~,~\stackrel{y_2}{-2})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}$

$JK=\sqrt{[5 - 4]^2 + [-2 - 2]^2}\implies JK=\sqrt{1^2+(-4)^2}\implies \boxed{JK=\sqrt{17}} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \overline{BC}\cong \overline{FG}~\hfill$

4 0

1 year ago